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fredd [130]
4 years ago
9

Find the lowest common denominator of and . A. x3y4 B. x2y3 C. xy4 D. x4y5

Mathematics
1 answer:
Blizzard [7]4 years ago
5 0
Lowest Common Denominator refers to lowes t common multiple. These expressions have two terms 'x' and 'y' and we want to choose the expression that has the highest power such that the other expressions can be multiplied into the common denominator.

For the 'x' term, the highest power is x⁴ and for the 'y' term, the highest power is y⁵

Common denominator of A, B, C, and D: x⁴y⁵




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Someone please help me with this asap
Leokris [45]

Answer:

All of these terms are dollar amounts.

Step-by-step explanation:

Here, x + y = 10 (where these numerals represent counts)

(1/2)x + (1/4)y = 4 (where (1/2), (1/4) and 4 are dollar amounts)

Let's eliminate y.  To accomplish this, mult. the 2nd eq'n by-4, obtaining

-2x - y = -16, and then combining this with the 1st equation, as follows:

-2x - y = -16

  x + y = 10

-------------------

 -x  = -6, or x = 6.  This represents the number of pens purchased by Terrance.  

Subbing 6 for x in the first equation, we get y = 4.  This represents the number of pencils he bought.

($0.50)x + ($0.25)y = $4.00 (dollar amounts)

5 0
3 years ago
There are 8 performers who will present their comedy acts this weekend at a comedy club. One of the performers insists on being
Natalija [7]
Well, the keyword here is One of the performers insist on being the last.

So, the amount of performers that we can arrange freely is 7 performers.

Different ways we can schedule their appearance is :

7 ! = 7 x 6  x 5 x 4 x 3 x 2 x 1
   
 
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hope this helps
5 0
3 years ago
Melody paid off a loan of $120,000 in 10 years. If she made a payment of $1,225 each month, then what was the simple interest ra
sdas [7]
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7 0
3 years ago
A rectangle field has an area of 300 square meters and a perimeter of 80 meters. what are the length and width of the field?
Yakvenalex [24]
By definition the area of a rectangle is:
 A = w * l
 The perimeter is:
 P = 2w + 2l
 Where,
 w: width
 l: long
 Substituting values:
 300 = w * l
 80 = 2w + 2l
 Solving the system of equations we have:
 l = 30 m
 w = 10 m
 Answer:
 
The length and width of the field are:
 
l = 30 m
 
w = 10 m
6 0
4 years ago
To determine whether 30 horses can be put into 7 stalls; so that in every stall there may be, either a single horse, or an odd n
algol [13]

Answer: No solutions

If i put any combo of horses of single or odd, always an even number at last stall.

3 0
3 years ago
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