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Alina [70]
4 years ago
9

Write a function named righttriangle() that accepts the lengths of two sides of a right triangle as the arguments a and

Mathematics
1 answer:
NeX [460]4 years ago
5 0
2 to 6 is one because angles can have different types
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3α – 3 (α + 2)<br> =10 please help
Sloan [31]

Step-by-step explanation:

3a-3(a+2)=10

3a-3a-6=10

+3 +3

6a-6=10

+6 +6

6a=16

3 0
3 years ago
What is the value of the function at x=−2? (98 points)
Archy [21]
The answer is c, y=2. if you look at the graph you can see that where x=-2 the line intersects the y axis at +2.
8 0
3 years ago
(a) What is the rate of change for each function? Show your work.
ikadub [295]
First. You have to look at what kind of proportionality it is.It is an Inverse Proportion.so you see the rate of change is 2.3
7 0
3 years ago
Find the area of a plane figure bounded by lines
natulia [17]

Answer: 4.5

<u>Step-by-step explanation:</u>

First, find the points of intersection by solving the system.

y = x² + 2x + 4

y = x + 6

Solve by substitution:

x² + 2x + 4 = x + 6   ⇒   x² + x - 2 = 0   ⇒   (x + 2)(x - 1) = 0   ⇒   x = -2, x = 1

Now, integrate from x = -2 to x = 1

\int\limits^1_2 {(x+6)-(x^{2}+2x+4) } \,    <em>the bottom of the integral is -2 </em>

= \int\limits^1_2 {x+6-x^{2}-2x-4 } \,

= \int\limits^1_2 {-x^{2}-x+2 } \,  

= \frac{-x^{3}}{3} - \frac{x^{2}}{2}+2x\int\limits^1_2 {} \,

= (\frac{-1^{3}}{3} - \frac{1^{2}}{2}+2(1)) - (\frac{-(-2)^{3}}{3} - \frac{(-2)^{2}}{2}+2(-2))

= (\frac{-1}{3} - \frac{1}{2} +2) - (\frac{8}{3} -\frac{4}{2} -4)

= \frac{-9}{3} + \frac{3}{2} +6

= -3 + 1.5 + 6

= 4.5


3 0
3 years ago
Please explain how you got your answers! (: Solve the problem by using the counting principle.
Natasha2012 [34]
A. The number of fabric-pattern-color combinations is 4 * 13 * 9 = 468

B. P(1st choice) = no of novels / total books = 3/6 = 1/2
    P(2nd choice) = no of remaining novels/ total remaining books = 2/5
    P(both novels) = 1/2 * 2/5 = 1/5          (without replacement assumed)

C. P(1st choice) = no of biographies / total books = 2/6 = 1/3
    P(2nd choice) = no of remaining biographies/ total remaining books =        1/5
    P(both biographies) = 1/3 * 1/5 = 1/15          (without replacement                assumed)

D. P(1st choice) = no of history books / total books = 1/6
    P(2nd choice) = no of novels/ total remaining books = 3/5
    P(a history, then a novel) = 1/6 * 3/5 = 1/10          (without replacement assumed)
7 0
3 years ago
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