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Alina [70]
4 years ago
6

Consider a company that selects employees for random drug tests. The company uses a computer to randomly select employee numbers

that range from 1 to
6857
6857. Find the probability of selecting a number divisible by 1000. Find the probability of selecting a number that is not divisible by 1000.
Mathematics
1 answer:
diamong [38]4 years ago
6 0
A. 999 numbers under 1000, so prob of picking one is 999/6296 = 0.1587 
<span>B. 6 numbers divisible by 1000, so prob 6/6296 = 0.000953 </span>
<span>C. (6296 - 6)/6296 = 1 - 0.000953 = 0.999047</span>
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maxonik [38]
The equation would be
g + (g + 9) = 45
2g + 9 = 45
- 9
2g = 36
÷ 2
g = 18
18 + 9 = 27
Girls: 18
Boys: 27
Hope this helps! Let me know if you have any questions :)
7 0
3 years ago
Ve, Carpet sells for $36 per square yard. How much will 8 square yards cost?​
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Step-by-step explanation:

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4 0
3 years ago
A ray of light with intensity lo falls vertically on the sur face of the sea and at ten meters deep its intensity is 10/3. Assum
seropon [69]

Answer:

intensity = \frac{Io}{15}

intensity = \frac{Io}{30}

depth = 333.33 m

Step-by-step explanation:

given data

deep = 10 m

intensity = Io

intensity = Io/3

to find out

intensity of light at 50 m and 100 m and 1/100 of initial intensity remain ?

solution

we know here that intensity is inversely proportional to deep so

intensity = k × \frac{1}{Deep}      .................1

here k is constant

so we have given 10 m deep so

\frac{Io}{3}  = \frac{k}{10}

so k = Io × \frac{10}{3}    ................2

so from equation 1 when 100 m deep and 50 m deep

intensity = k × \frac{1}{Deep}

intensity =  Io × \frac{10}{3} × \frac{1}{50}

intensity = \frac{Io}{15}

and

intensity =  Io × \frac{10}{3} × \frac{1}{100}

intensity = \frac{Io}{30}

and

at intensity Io/100

intensity = k × \frac{1}{Deep}

\frac{Io}{100}  =  Io × \frac{10}{3} × \frac{1}{D}

D = 333.33 m

so depth = 333.33 m

3 0
3 years ago
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