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Simora [160]
3 years ago
12

I need help.............

Mathematics
1 answer:
Grace [21]3 years ago
7 0

c= b - bx \\bx = b-c\\x= \frac{b-c}{b}

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Prove or disprove (from i=0 to n) sum([2i]^4) <= (4n)^4. If true use induction, else give the smallest value of n that it doe
ddd [48]

Answer:

The statement is true for every n between 0 and 77 and it is false for n\geq 78

Step-by-step explanation:

First, observe that, for n=0 and n=1 the statement is true:

For n=0: \sum^{n}_{i=0} (2i)^4=0 \leq 0=(4n)^4

For n=1: \sum^{n}_{i=0} (2i)^4=16 \leq 256=(4n)^4

From this point we will assume that n\geq 2

As we can see, \sum^{n}_{i=0} (2i)^4=\sum^{n}_{i=0} 16i^4=16\sum^{n}_{i=0} i^4 and (4n)^4=256n^4. Then,

\sum^{n}_{i=0} (2i)^4 \leq(4n)^4 \iff \sum^{n}_{i=0} i^4 \leq 16n^4

Now, we will use the formula for the sum of the first 4th powers:

\sum^{n}_{i=0} i^4=\frac{n^5}{5} +\frac{n^4}{2} +\frac{n^3}{3}-\frac{n}{30}=\frac{6n^5+15n^4+10n^3-n}{30}

Therefore:

\sum^{n}_{i=0} i^4 \leq 16n^4 \iff \frac{6n^5+15n^4+10n^3-n}{30} \leq 16n^4 \\\\ \iff 6n^5+10n^3-n \leq 465n^4 \iff 465n^4-6n^5-10n^3+n\geq 0

and, because n \geq 0,

465n^4-6n^5-10n^3+n\geq 0 \iff n(465n^3-6n^4-10n^2+1)\geq 0 \\\iff 465n^3-6n^4-10n^2+1\geq 0 \iff 465n^3-6n^4-10n^2\geq -1\\\iff n^2(465n-6n^2-10)\geq -1

Observe that, because n \geq 2 and is an integer,

n^2(465n-6n^2-10)\geq -1 \iff 465n-6n^2-10 \geq 0 \iff n(465-6n) \geq 10\\\iff 465-6n \geq 0 \iff n \leq \frac{465}{6}=\frac{155}{2}=77.5

In concusion, the statement is true if and only if n is a non negative integer such that n\leq 77

So, 78 is the smallest value of n that does not satisfy the inequality.

Note: If you compute  (4n)^4- \sum^{n}_{i=0} (2i)^4 for 77 and 78 you will obtain:

(4n)^4- \sum^{n}_{i=0} (2i)^4=53810064

(4n)^4- \sum^{n}_{i=0} (2i)^4=-61754992

7 0
3 years ago
1 1/3 x 1/14<br> Help please
nikklg [1K]

Step-by-step explanation:

=11/3×1/14

=3.67×0.07

=0.2568

7 0
2 years ago
Read 2 more answers
which graph represents a line with a slope of -2/3 and a u intercept equal to that of theme u =2/3×-2​
Usimov [2.4K]

Answer:

Step-by-step explanation:

6 0
3 years ago
If √(0.09×0.09×x) = 0.09 × 0.09×√z, then the value of x/y is____.​
OLEGan [10]

Given that-

√(0.09×0.09×x) = 0.09×0.09×√z

On squaring both sides then

⇛[√(0.09×0.09×x) ]² = (0.09×0.09×√z)²

⇛ 0.09×0.09×x= (0.09)²×(0.09)²×(√z)²

⇛ (0.09)² × x = (0.09)²×(0.09)²×z

⇛ (0.09)² × x/z = (0.09)²×(0.09)²

⇛x/z = (0.09)²×(0.09)²/(0.09)²

⇛x/z = (0.09)²

⇛x/z = 0.09×0.09

⇛x/z = 0.0081

<u>Answer</u><u>:</u><u>-</u> Hence the value of x/z will be 0.0081 r respectively.

3 0
2 years ago
4
Alenkasestr [34]

Answer:

11

need more characters

8 0
3 years ago
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