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Llana [10]
3 years ago
11

Is rolling an even number on a number cube an outcome or an event?

Mathematics
1 answer:
timofeeve [1]3 years ago
8 0
It is an outcome, due to the probability of it happening.
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What is the value for y?<br> Enter your answer in the box.<br> y=
rjkz [21]

Answer:

28

Step-by-step explanation:

4 0
3 years ago
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Conrad paid $52.26 for a pair of shoes. Michelle paid $3.89 more for a pair of shoes than Conrad paid for his.
QveST [7]

Answer:

$60.30

Step-by-step explanation:

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3 years ago
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raj and his sister zia are both at secondary school. Raj is three years older than zia. the sum of the squares of their ages is
Cerrena [4.2K]

Let Zia's age be = x years

Raj is three years older than Zia, so Raj's age = x+3 years

As the sum of the squares of their ages is 369, so

x^{2}+(x+3)^{2}=369

x^{2}+x^{2}+6x+9=369

2x^{2}+6x+9=369

2x^{2}+6x-360=0

Factoring 2 out we have,

x^{2}+3x-180=0

Now solving this equation,

x^{2}+15x-12x-180=0

x(x+15)-12(x+15)

(x+15)(x-12)

x=-15 and x=12

Neglect the negative value as x cannot be negative

So x=12

Hence, Zia's age is 12 years and

Raj's age is 12+3 = 15 years


4 0
3 years ago
What is a real-world problem that can be modeled by the equation 1.25 = 0.75x + 50 ?
goldenfox [79]
<span>1.25 = 0.75x + 50
0.75x = 1.25 - 50
0.75x = -48.75
x = -48.75 / 0.75
x = 65</span>
7 0
3 years ago
At Pike Place Fish Market in Seattle, customers can purchase a variety of different types of seafood. One type of seafood sold a
allsm [11]

Answer:

z=1.28

And if we solve for a we got

a=3.6 +1.28*0.8=4.624

So the value of height that separates the bottom 90% of data from the top 10% is 4.624.

So then the best answer for this case would be:

 C. 4.64

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(3.6,0.8)  

Where \mu=3.6 and \sigma=0.8

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.1   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.28

And if we solve for a we got

a=3.6 +1.28*0.8=4.624

So the value of height that separates the bottom 90% of data from the top 10% is 4.624.

So then the best answer for this case would be:

 C. 4.64

8 0
3 years ago
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