Answer:
B. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 1 do not form right angles.
E. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 4 do not form right angles.
Step-by-step explanation:
P1: 12^2+15^2=20^2 144+225=400 369=400
P2: 16^2+30^2=34^2 256+900=1156 1156=1156
P3: 20^2+21^2=29^2 400+441=841 841=841
P4: 18^2+20^2=26^2 324+400=676 724=676
So the answers are B and E
Answer:
0
Step-by-step explanation:
You use BIDMAS
Brackets: 10÷5=2
-2 ² =-4
Multiplication: -4×2=-8
Addition: -8+2=-6
Subtraction: 6--6=0
Answer:
X=6,-4
Step-by-step explanation:
0=x^2-2x-24
First substitute x with 6
0=(6)^2-2(6)-24
36-12-24
=0
Now try -4
0=(-4)^2-2(-4)-24
Two negative numbers time each other turns it into a positive number -4 x -4=16
24-24=0
Answer:
12 + 8k² + k³ - 9k⁴
Step-by-step explanation:
(8 + k³ - 6k⁴) + (4 - 3k⁴ + 8k²)
8 + k³ - 6k⁴ + 4 - 3k⁴ + 8k²
(8 + 4) + (8k²) + (k³) + (-6k⁴ -3k⁴)
(12) + (8k²) + (k³) + (-9k⁴)
12 + 8k² + k³ - 9k⁴
<h2>
Explanation:</h2>
As I understand, the given equation is:
So we need to write this into general form. The general form of the equation of a line is given by:
Where A and B can't be zero at the same time. So subtracting 5y from both sides: