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lorasvet [3.4K]
3 years ago
5

Answer part B please

Mathematics
2 answers:
asambeis [7]3 years ago
5 0
1.5 I think sorry if I’m wrong but I hope this helps
oksano4ka [1.4K]3 years ago
4 0
1:5

Steps:
1. Add all the numbers
2. Take Derek’s number of votes and turn step 1’s answer and Derek’s number of votes into a ration:
3. You will now have 36:180
4. Simplify by a number they both share (36).
5. Your new simplified answer would be 1:5.
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The measure of angle A is 15°, and the length of side
dangina [55]

Answer:

Part 1) AB=30.9\ units

Part 2) AC=29.9\ units

Step-by-step explanation:

The picture of the question in the attached figure

Part 1

Find the length side AB

we know that

sin(A)=\frac{BC}{AB} ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

sin(15^o)=\frac{8}{AB}

solve for AB

AB=\frac{8}{sin(15^o)}=30.9\ units

Part 2

Find the length side AC

we know that

tan(A)=\frac{BC}{AC} ----> by TOA (opposite side divided by the adjacent side)

substitute the given values

tan(15^o)=\frac{8}{AC}

solve for AC

AC=\frac{8}{tan(15^o)}=29.9\ units

8 0
3 years ago
Helppp!!!! please!!!
Anna007 [38]

Answer:

608 ft^2

Step-by-step explanation:

The formula for calculating surface area of a triangular prism is

bh + 2ls + lb (b : base, h : height, l : length)

12×8 + 2×16×10 + 16×12 = 608 ft^2

7 0
3 years ago
Find the side of to cube<br> whose volume is<br> 5.832cm3
Scorpion4ik [409]

Answer:

1.8cm

Step-by-step explanation:

Use the volume of cube formula.

\displaystyle V=s^3

\displaystyle5.832=s^3

\displaystyle\sqrt[3]{5.832} =s

\displaystyle s=1.8

3 0
3 years ago
Read 2 more answers
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kozerog [31]

Answer:

yes pls

Step-by-step explanation:

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What is the median ?
mel-nik [20]
The median value of a range of values.

denoting or relating to a value or quantity lying at the midpoint of a frequency distribution of observed values or quantities, such that there is an equal probability of falling above or below it.

a straight line drawn from any vertex of a triangle to the middle of the opposite side.
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