The table represents the function f (x) = 2 x + 1.

Mathematics

2 answers:

Salsk061 [2.6K]3 years ago

5 0

Answer:

Step-by-step explanation:

In the table, we are given the points [ (-3, -5), (2, y), (5, 11), (8, 17) ]

We are given the equation [ f(x) = 2x + 1 ] where 2 = slope and 1 = y intercept.

We need to find the value of "y".

y2-y1/x2-x1

y-(-5)/2-(-3) = 2

y+5/5 = 2

y = 5

Best of Luck!

Elena L [17]3 years ago

4 0

Answer:

Step-by-step explanation:

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Please explain and tell me how to do it please

dsp73

The answer is b) y = 3x + 3.

To find this, we first need to find the slope. The slope formula is listed below.

m = (y2 - y1)/(x2 - x1)

In this equation, m is the slope, and (x1, y1) is the first point, where (x2, y2) is the second point. We'll use (2, 9) and (3, 12) for the points.

m = (y2 - y1)/(x2 - x1)

m = (12 - 9)/(3 - 2)

m = 3/1

m = 3

Now that we have the slope at 3. we can use slope intercept form and one point to solve for the y-intercept. We'll use (2, 9) as the point.

y = mx + b

9 = 3(2) + b

9 = 6 + b

3 = b

When we use the slope and intercept together to get the equation. y = 3x + 3

8 0

3 years ago

where does the graph of the function y=tan(x) have asymptotes? at the values of x where cos(x)=0 at the values of x where sin(x)

Gnom [1K]

Answer: at the values where cos(x) = 0

Justification:

1) tan(x) = sin(x) / cos(x).

2) functions have vertical asymptotes at x = a if Limit of the function x approaches a is + or - infinity.

3) the limit of tan(x) approaches +/- infinity where cos(x) approaches 0.

Therefore, the grpah of y = tan(x) has asymptotes where cos(x) = 0.

You can see the asympotes at x = +/- π/2 on the attached graph. Remember that cos(x) approaches 0 when x approaches +/- (n+1) π/2, for any n ∈ N, so there are infinite asymptotes.