Answer:
H(s)=(∫_(t=o)^∞▒〖x(t)e^(-st) dt〗)/(∫_(t=o)^∞▒〖y(t) e^(-st) dt〗)
Step-by-step explanation:
L{f(t)}=F(s)=∫_(t=0)^∞▒〖f(t)e^(-st) dt〗
x + y = 3 x - y = 1 --------- 2x + 0y = 4 2x = 4 (2x)/2 = 4/2 x = 2
hope i am right
r < 4
r+6<10
205??????
sorry if I didn't get it right
it's A