Answer:
−2 is a member of the domain of f.
f(0) > 0
Step-by-step explanation:
Statement 1 is TRUE. Domain value includes set of values of x of the function. -2 is plotted on the x-axis on the graph. Therefore, it is a member of domain of f.
Statement 2 is incorrect. Range includes all possible y-values of the function. On the graph, no y-value plotted is -2. Therefore, -2 is NOT a member of the range of f.
Statement 3 is TRUE.
f(0) is approximately 2.2 on the graph. i.e. at x = 0, y ≈ 2.2.
Therefore, f(0) > 0.
Statement 4 is INCORRECT.
f(2) = 1, that is at x = 2, y = 1 as seen in the graph. Therefore, f(2) is not greater than 2.
21. 1/7 3/8 1/2
23. 3 5/8 3 3/8 3 1/2
25. 1/6 3/4 2/3
Answer:
B is the variable and A is the numerical coefficient
Answer:
Solving for t : t=5+2r/5
Solving for r : r=-25/2+5t/2
Step-by-step explanation: Move all of your terms that don't contain r to the right side and solve. Move all terms that don't contain t to the right side and solve.
Hope this helps you out! ☺ I just solved it and I don't have any choices to go off of and so I just solved it. Sorry if it's wrong. ☺
A(b-c)=ab-ac
(1/7)(1/3h-1/2)=(1/7)(1/3h)-(1/7)(1/2)=1/21h-1/14
now we gots
6 and 1/7+1/21h-1/14
rearange
6 and 1/7-1/14+1/21h
make common denom which is 14
6 and 2/14-1/14+1/21h
6 and 1/14+1/21h