The number of $1, $5 and $10 are 49, 44 and 22 respectively.
<h3>How to use equation to find the number of bills?</h3>
There are 3 denominations of bills in a wallet: $1, $5, and $10.
There are 5 fewer $5-bills than $1-bills.
let
x = number of $1 bills
Hence,
number of $5 bills = x - 5
There are half as many $10-bills as $5-bills.
number of $10 bills = 1 / 2 (x - 5)
Therefore,
x + x - 5 + 1 / 2 (x - 5) = 115
2x - 5 + 1 / 2 x - 5 / 2 = 115
2x + 1 / 2 x - 5 - 5 / 2 = 115
5 / 2 x - 7.5 = 115
2.5x = 115 + 7.5
x = 122.5 / 2.5
x = 49
Number of $1 bills = 49
Number of $5 bills = 49 - 5 = 44
Number of $10 bills = 1 / 2 (49 - 5) = 22
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The correct answer is: Option (D) Take the square root of both sides
Explanation:
Given equation:
9x^2 -24x + 16 = 11
Step 1:
9x^2 - 12x - 12x + 16 = 11
3x(3x - 4) - 4(3x - 4) = 11
(3x-4)^2 = 11
Step 2:Take square-root on both sides (Option D)
![\sqrt{(3x-4)^2} = \sqrt{11}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%283x-4%29%5E2%7D%20%3D%20%20%5Csqrt%7B11%7D)
![(3x-4) = \sqrt{11} \\ x = \frac{ \sqrt{11} + 4 }{3}](https://tex.z-dn.net/?f=%283x-4%29%20%3D%20%5Csqrt%7B11%7D%20%5C%5C%20%20x%20%3D%20%20%5Cfrac%7B%20%5Csqrt%7B11%7D%20%2B%204%20%7D%7B3%7D%20)
(value of x)
The answer would be y=-2x-4
The range are the y values.
Range of {(-3, 4), (5, 11), (9, -1), (10, 13)} is {4, 11, -1, 13}