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ohaa [14]
3 years ago
9

I really need help i don’t understand !!!!!!

Mathematics
1 answer:
inn [45]3 years ago
6 0

Answer:

y+2 = -4/5(x-3)

Step-by-step explanation:

The point slope form of a line is

y-y1 = m(x-x1) where m is the slope and (x1,y1) is the point

y - -2 = -4/5(x-3)

y+2 = -4/5(x-3)

You might be interested in
Answer this equation
Rudik [331]

Answer:

The solution to the box is

a = 2.1

b = 5.9

c = 0.9

d = 10

Step-by-step explanation:

To answer the equation, we simply name the boxes a,b,c and d.

Such that

a + b = 8 ---- (1)

b - c = 5 ------ (2)

d * c = 9 ------ (3)

a * d = 21 ------- (4)

Make d the subject of formula in (3)

d * c = 9 ---- Divide both sides by c

d * c/c = 9/c

d = 9/c

Substitute 9/c for d in (4)

a * d = 21

a * 9/c = 21

Multiply both sides by c

a * 9/c * c = 21 * c

a * 9 = 21 * c

9a = 21c ------ (5)

Make b the subject of formula in (1)

a + b = 8

b = 8 - a

Substitute 8 - a for b in (2)

b - c = 5

8 - a - c = 5

Collect like terms

-a - c = 5 - 8

-a - c = -3

Multiply both sides by -1

-1(-a - c) = -1 * -3

a + c = 3

Make a the subject of formula

a = 3 - c

Substitute 3 - c for a in (5)

9a = 21c becomes

9(3 - c) = 21c

Open bracket

27 - 9c = 21c

Collect like terms

27 = 21c + 9c

27 = 30c

Divide both sides by 30

27/30 = 30c/30

27/30 = c

0.9 = c

c = 0.9

Recall that a = 3 - c

So, a = 3 - 0.9

a = 2.1

From (1)

a + b = 8

2.1 + b = 8

b = 8 - 2.1

b = 5.9

From (3)

d * c = 9

Substitute 0.9 for c

d * 0.9 = 9

Divide both sides by 0.9

d * 0.9/0.9 = 9/0.9

d = 9/0.9

d = 10.

Hence, the solution to the box is

a = 2.1

b = 5.9

c = 0.9

d = 10

3 0
3 years ago
Q(x)=4x2-3x3+8x is it a cubic trinomial​
Norma-Jean [14]

Answer:

Yes

Answer:    x = 0

Step-by-step explanation:

Yes it is.

Down is the answer how to solve this equation and the steps.

Step  1  :

Equation at the end of step  1  :

 qx -  (((4 • (x2)) -  3x3) +  8x)  = 0  

Step  2  :

Equation at the end of step  2  :

 qx -  ((22x2 -  3x3) +  8x)  = 0  

Step  3  :

Step  4  :

Pulling out like terms :

4.1     Pull out like factors :

  qx + 3x3 - 4x2 - 8x  =  

 x • (q + 3x2 - 4x - 8)  

Equation at the end of step  4  :

 x • (q + 3x2 - 4x - 8)  = 0  

Step  5  :

Theory - Roots of a product :

5.1    A product of several terms equals zero.  

When a product of two or more terms equals zero, then at least one of the terms must be zero.  

We shall now solve each term = 0 separately  

In other words, we are going to solve as many equations as there are terms in the product  

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

5.2      Solve  :    x = 0  

 Solution is  x = 0

Solving a Single Variable Equation :

5.3     Solve   q+3x2-4x-8  = 0

In this type of equations, having more than one variable (unknown), you have to specify for which variable you want the equation solved.

Answer:  x = 0

Hope this helps.

7 0
3 years ago
If the Circumfernce of a circle is 25.1, please find: -The radius -The diameter -The area
dsp73

Answer:

Radius = 1.997

Diameter = 3.993

Area = 12.549

5 0
3 years ago
PLEASE HELP ASAP PLEASE HELP IM ON A TEST!!!!
qaws [65]

Answer:

2,520 meters

Step-by-step explanation:

Just multiply :)

6 0
3 years ago
Can you guys please help me? This is due tomorrow, thanks so much​
wariber [46]

Answer:

<em>Graph given in </em><em>Question 18</em><em> is </em><em>a function</em><em> and the graph given in </em><em>Question 19</em><em> is </em><em>not a function</em><em>. Just check the </em><em>attached figure.</em>

Step-by-step explanation:

From the given graph of a relation, it is easy to establish whether the given relation is a function or not. In order to determine the nature of the relation, there is vertical line test. This test can be done by drawing any vertical line crossing the graph of the given relation. This vertical line has a constant x -a line having constant x.

If this vertical line crosses the graph multiple times, then we can determine that the relation would not be a function. It means the graph contains multiple values of y for a single value of x. This violates the condition of a relation to be a function. Hence, the relation would not be a graph.

But, if the vertical line crosses the graph only one time, then we can determine that the given relation would be a function. It means the graph does not contain multiple values of y for a single value of x.

<em>Solution of the Graph given in Question 18:</em>

From the given graph of a relation, that sounds like a circle. It means the relation shown in current graph is not a function. The reason is simple. If we draw a vertical line, then the line would cross the graph twice. Hence, the given graph of a relation is not a function.

Just check that the value of x=1 will have two y values i.e (1, 5) and (1, -1). Also, at origin, for a value of x = 0, there are multiple values of y. Hence, the graph is not a not a function, but just a relation. Just check the <em>attached  figure.</em>

<em>Solution of the Graph given in Question 19:</em>

From the given graph of a relation, it is clear that the graph is a function. The reason is simple. If we draw a vertical line, then the line would cross the graph only one time. Hence, the given graph of a relation is a function.

Just check that the points (0, 0), (2, 3), (-1, 3), (-3, 3) and (1, -3) all make a function as each input value yields an exactly one output function. Hence, the given graph of the relation is a graph. Just check the <em>attached  figure.</em>

<em>Keywords: function, relation, ordered pairs, graph, vertical line test</em>

<em>Learn about the graph functions from brainly.com/question/4708956</em>

<em>#learnwithBrainly</em>

4 0
3 years ago
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