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Serjik [45]
2 years ago
6

The triangle and the rectangle below have the same area.

Mathematics
1 answer:
user100 [1]2 years ago
5 0

Answer:

w = 2.5

Step-by-step explanation:

6cm * wcm = 5cm * 6cm / 2;  divide both sides by 6cm

wcm = 5cm / 2; calculate

wcm = 2.5cm; divide both sides by 1cm ;)

w = 2.5

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The measures of a triangle are shown below. sovle for x​
Zigmanuir [339]

Answer:

x=16

Step-by-step explanation:

In a triangle the sum of all angle measures will always equal 180 degrees.

A+B+C=180

From the information given we know that the angle measures are:

A= 90, B=(5x-3), C=(x+9)

When you input this into the equation above you get:

90+(5x-3)+(x+9)=180

First, subtract 90 from both sides

(5x-3)+(x+9)=90

Next let's combine like terms

6x+6=90

Subtract 6 from both sides

6x=84

divide both sides by 6

x=16

<em>plz mark me brainliest. :)</em>

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2 years ago
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4 0
3 years ago
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zheka24 [161]

Step-by-step explanation:

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6 0
2 years ago
(GIVING BRAINLIEST!!!)
Lapatulllka [165]

Answer:

each bag weights 1,500 grams

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
Two cargo ships are sailing a direct course into harbor. Ship A is 22 miles from harbor. Ship Bis sailing into harbor on a cours
s344n2d4d5 [400]

Answer:

The distance of ship B from the Harbor is 32.26 miles

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Equations.

I have added a visual aid of the problem. As we can see the courses of both ship to the harbor forms a triangle with ship B being the hypotenuse. Since we are given the distance of the course for ship A and the angle between both ships, we can use this information with the <u>COSINE operator</u> to solve for the length of the course of ship B.

cos(x) = \frac{adjacent}{hypotenuse}

cos(47) = \frac{22miles}{hypotenuse} .... flip both fractions.

\frac{1}{cos(47)} = \frac{hypotenuse}{22miles} .... multiply both sides by 22

\frac{22mi}{cos(47)} = hypotenuse

32.26mi = hypotenuse = B

So the distance of ship B from the Harbor is 32.26 miles

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

3 0
3 years ago
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