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Eva8 [605]
3 years ago
8

I need help with all of these. I’m bad at them. Tell me how you solved for this please

Mathematics
1 answer:
Greeley [361]3 years ago
3 0

1) online has the lower unit price

27.25 / 5 = 5.45

32.16 / 6 = 5.3583333.... rounded it would be

5.35

2) The cost of 7 pounds would be 103.18

73.70 / 5 = 14.74 (cost of one pound)

14.74 x 7 = 103.18

3) The scarf in October costed more

13.35 / 3 = 4.45 (one scarf)

22.65 / 5 = 4.53

hope this helps


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18. Jackie drives 160 miles from Gary, Indiana to
astra-53 [7]

Answer:

11 hours and 15 minutes (11.25)

Step-by-step explanation:

make a ratio

160:4.5

240/160=1.5

so 1 and 1/2 intervals of 4.5 hours

4.5+4.5= 9

4.5/2=2.25

9+2.25=11.25

6 0
2 years ago
The price of a video game at Game Word has increased from $36 to $45 each. What was the percent change?
andriy [413]

Step-by-step explanation:

price difference= $45-$36

=$9

now,

x% of $45=$9

or, x/100 ×45 =9

or, x/20 ×9=9

or, x/20=1

therefore, x= 20%

3 0
2 years ago
PLEASE HELP!!! Shasha and Alan are both running on the track Shasha begins at the starting line and is running 5 feet per second
Nina [5.8K]

Answer:

All you have to do is multiply 5 and 3 by specific gaps in between new numbers then subtract 30. Keep doing that until you get evenly matched numbers.

Step-by-step explanation:

The answer is 15, it would take 15 seconds for Alan to reach Sasha.

3 0
2 years ago
When an electric current passes through two resistors with resistance r1 and r2, connected in parallel, the combined resistance,
kondaur [170]

Answer:

a)

The combined resistance of a circuit consisting of two resistors in parallel is given by:

\frac{1}{R}=\frac{1}{r_1}+\frac{1}{r_2}

where

R is the combined resistance

r_1, r_2 are the two resistors

We can re-write the expression as follows:

\frac{1}{R}=\frac{r_1+r_2}{r_1r_2}

Or

R=\frac{r_1 r_2}{r_1+r_2}

In order to see if the function is increasing in r1, we calculate the derivative with respect to r1: if the derivative if > 0, then the function is increasing.

The derivative of R with respect to r1 is:

\frac{dR}{dr_1}=\frac{r_2(r_1+r_2)-1(r_1r_2)}{(r_1+r_2)^2}=\frac{r_2^2}{(r_1+r_2)^2}

We notice that the derivative is a fraction of two squared terms: therefore, both factors are positive, so the derivative is always positive, and this means that R is an increasing function of r1.

b)

To solve this part, we use again the expression for R written in part a:

R=\frac{r_1 r_2}{r_1+r_2}

We start by noticing that there is a limit on the allowed values for r1: in fact, r1 must be strictly positive,

r_1>0

So the interval of allowed values for r1 is

0

From part a), we also said that the function is increasing versus r1 over the whole domain. This means that if we consider a certain interval

a ≤ r1 ≤ b

The maximum of the function (R) will occur at the maximum value of r1 in this interval: so, at

r_1=b

6 0
3 years ago
Correct and best answer gets brainliest.
Nuetrik [128]
Im pretty sure the answer is c) 136
4 0
3 years ago
Read 2 more answers
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