Standard form is just putting (in this case) variables in alphabetical order. First we simplify- 2x+4=4y would become 1/2x+1=y. This is already in standard form, as numbers w/o variables come at the end. simplifying the next one is more tricky. first you get a variable/number alone- 9-2x-2y=4x+3 9-2y=6x+3 6-2y=6x 1-1/3y=x 1=x+1/3y 3=x+y x+y=3 sorry if I was wrong and not of any help, But I do believe this is correct.
What standard for is is when all the variables are on one side in order, without being expressed as a decimal or fraction.
To put 2x+4=4y in standard form, first subtract 4 from both sides.
2x=4y-4 Now, subtract 4y from both sides.
2x-4y=-4
Now the equation is in standard form.
To put the next equation in order, first distribute -2 into (x-y) to get:
9-2x+2y=4x+3
Because one variable cannot be on both sides, subtract 4x from both sides.
9-6x+2y=3
Now subtract 9 to both sides:
-6x+2y=-6
My teacher last year did not like when the first variable in standard form was negative. If that is the case with your teacher, distribute -1 into everything on both sides of the equation. That would look like:
6x-2y=6
If your teacher is impartial, then you can leave there equation how it was.
This makes a triangle with one side of 13 one of 5 and the other x. In this case the x is 12 because 13,12,5 triangles are a special case, a Pythagorean triple. 5^2+12^2=13^2 25+144=169 169=169
V 1 = 500 mph, v 2 = 50 mph The resultant velocity: v r² = v 1 ² + v 2 ² v r ² = 500² + 50² = 250,000 + 2,500 = 252,500 v r = √252,500 = 502.49378 ≈ 502.49 mph Answer: the magnitude of the resultant velocity is 502.49 mph.
when subtracting you could reverse it and add so add back the 2.50 to the 5 and if he spent half of what he had left the that would mean he had another 5 dollars. in total he had 12.50$
