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Effectus [21]
3 years ago
12

PLEASE HELP!!

Mathematics
2 answers:
sp2606 [1]3 years ago
5 0
Standard form is just putting (in this case) variables in alphabetical order. First we simplify- 2x+4=4y would become 1/2x+1=y. This is already in standard form, as numbers w/o variables come at the end. simplifying the next one is more tricky. first you get a variable/number alone-
9-2x-2y=4x+3
9-2y=6x+3
6-2y=6x
1-1/3y=x
1=x+1/3y
3=x+y
x+y=3
sorry if I was wrong and not of any help, But I do believe this is correct.
lbvjy [14]3 years ago
3 0
What standard for is is when all the variables are on one side in order, without being expressed as a decimal or fraction.

To put 2x+4=4y in standard form, first subtract 4 from both sides.

2x=4y-4
Now, subtract 4y from both sides.

2x-4y=-4

Now the equation is in standard form.

To put the next equation in order, first distribute -2 into (x-y) to get:

9-2x+2y=4x+3

Because one variable cannot be on both sides, subtract 4x from both sides.

9-6x+2y=3

Now subtract 9 to both sides:

-6x+2y=-6

My teacher last year did not like when the first variable in standard form was negative. If that is the case with your teacher, distribute -1 into everything on both sides of the equation. That would look like:

6x-2y=6

If your teacher is impartial, then you can leave there equation how it was.

So the answers are:

2x-4y=-4
-6x+2y=-6 (or 6x-2y=6)
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The volume of the shape

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\begin{gathered} \text{External radius = 4ft + 1ft } \\ =\text{  5ft} \end{gathered}

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\begin{gathered} =\text{ Volume of cylinder with a radius of 5ft - Volume of cylinder with a radius of 4ft} \\ =\text{ }\frac{\pi\text{ }\times5^2\text{ }\times\text{ 12}}{2}\text{ - }\frac{\pi\text{ }\times4^2\text{ }\times\text{ 12}}{2} \\ =\text{ 471.239 - }301.593 \\ =169.65ft^3 \end{gathered}

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