Question

N(17+x)=34x−r I need to solve for x

Answer 1

Answer:

The value of x is, $x= \frac{17N+r}{34-N}$

Explanation:

Given: $N(17+x)=34x-r$

Distributive Property states that when a number is multiplied by the sum of two numbers, the first number can be distributed to both of those numbers and multiplied by each of them separately.

If $a\cdot(b+c) =a\cdot b + a\cdot c$

Now, using distributive property on left hand side of the given expression as:

$N\cdot 17+N\cdot x = 34x-r$ or $17N+Nx = 34x-r$

Addition Property of equality state that we add the same number from both sides of an equation.

Add r to both sides of an equation:

$17N+Nx+r=34x-r+r$

Simplify:

$17N+Nx+r=34x$

Subtraction Property of equality state that we subtract the same number from both sides of an equation.

Subtract Nx from both sides of an equation;

$17N+Nx+r-Nx=34x-Nx$

Simplify:

$17N+r=34x-Nx$

or

$17N+r=x(34-N)$

Division Property of equality states that we divide the same number from both sides of an equation.

Divide by (34-N) to both sides of an equation;

$\frac{17N+r}{34-N}= \frac{x(34-N)}{34-N}$

On Simplify:

$x= \frac{17N+r}{34-N}$

Answer 2

The value of X will be (17N + r)/ (34-N).

N(17 + x) = 34x -r

17N + Nx = 34x - r

Collect the x together.

17N/N + 34x -r

Therefore the answer will be

(17N +r) / (34-N).