Number one is 33 < 1118 so true and number two is infinite solutions so it would be true as well
Below are the choices:
A. 80 mL of the 3.5% solution and 120 mL of the 6% solution
<span>B. 120 mL of the 3.5% solution and 80 mL of the 6% solution </span>
<span>C. 140 mL of the 3.5% solution and 60 mL of the 6% solution </span>
<span>D. 120 mL of the 3.5% solution and 80 mL of the 6% solution
</span>
Let fraction of 3.5% in final solution be p.
<span>p * 3.5 + (1 - p) * 6 = 4.5 </span>
<span>3.5p + 6 - 6p = 4.5 </span>
<span>2.5p = 1.5 </span>
<span>p = 3/5 </span>
<span>3/5 * 200 = 120 </span>
<span>Therefore the answer is B. 120 ml of 3.5% and 80 ml of 6%.</span>
Answer:
190
Step-by-step explanation:
Data provided in the question:
Confidence level = 99%
Therefore,
α = 1% = 0.01
[ from standard normal table ]
z-value for 
= 2.58
Margin of error, E = $0.06
Standard deviation, σ = $0.32
Now,
n = 
Here,
n is the sample size (or the minimum number of gas stations )
on substituting the respective values, we get
=
= 
= 13.76²
= 189.3376 ≈ 190
Hence,
minimum number of gas stations that she should include in her sample is 190
Answer:
$968
Step-by-step explanation:
x= the money John originally had in his savings account
The statement says that John spent $88 on a radio and 1/4 of what was left on presents for his friends. This means that the remaining money is 3/4 of the total amount minus the money spent on the radio:
3/4(x-88)
Then, it says that of the money remaining, John put 4/11 into a checking account and the last remaining $420 was left to charity. Since, he spent 4/11 of the remining 3/4(x-88), the remaining is 7/11 of that and that remaining is equal to $420 that was the money left at the end:
7/11(3/4(x-88))= 420
21/44(x-88)=420
21/44x-42=420
21/44x=462
x=968
According to this, the money that John originally had in his savings account was $968.
He spent $88 on a radio: 968-88= 880
1/4 of what was left on presents for his friends: 880/4= 220
880-220=660
Of the money remaining, John put 4/11 into a checking account: 660*(4/11)=240
the last remaining $420 was left to charity: 660-240= 420
By elimination:
y = 3x - 1
y = 2x + 2
Subtract the second equation from the first
0 = x - 1
y = 2x + 2
Subtract the first equation from the second
0 = x - 1
y = x + 3
Subtract the first equation from the second again
0 = x - 1
y = 4
Subtract x from both sides of the first equation
- x = - 1
y = 4
Divide the first equation by (-1)
x = 1
y = 4
<h3>
So, the solution is x = 1 and y = 4 {or: (1, 4)}</h3>
