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kompoz [17]
3 years ago
10

Which of the following is not a type of user account? A. Administrator b. Guest c. Group d. Standard

Computers and Technology
1 answer:
Arlecino [84]3 years ago
5 0
I've never heard of a group account so I'm going with.
C. Group
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How does a cloud-first strategy differ from other approaches to cloud?
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Cloud-first strategy differ from other approaches as It keeps all the services performed by legacy systems while moving to the Cloud in a staggered approach.

<h3>What is a cloud first strategy?</h3>

The change of cloud computing has brought about  “cloud-first” strategy.

This  is known to be a way to computing that tells that a firm should look first to cloud solutions when creating new processes or taking in old processes before taking in non-cloud-based solutions.

Note that Cloud-first strategy differ from other approaches as It keeps all the services performed by legacy systems while moving to the Cloud in a staggered approach.

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2 years ago
What is cryptocurrency ? I need to do a research one it please help!
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8 0
3 years ago
⦁ Consider transferring an enormous file of L bytes from Host A to Host B. Assume an MSS of 536 bytes. ⦁ What is the maximum val
timurjin [86]

Answer:

a)  There are approximately  2^32 = 4,294,967,296 possible number of the sequence. This number of the sequence does not increase by one with every number of sequences but by byte number of data transferred. Therefore, the MSS size is insignificant. Thus, it can be inferred that the maximum L value is representable by 2^32 ≈ 4.19 Gbytes.

b)  ceil(2^32 / 536) = 8,012,999

The segment number is 66 bytes of header joined to every segment to get a cumulative sum of 528,857,934 bytes of header. Therefore, overall number of bytes sent will be 2^32 + 528,857,934 =  4.824 × 10^9 bytes.  Thus, we can conclude that the total time taken to send the file will be 249 seconds over a 155~Mbps link.

Explanation:

a)  There are approximately  2^32 = 4,294,967,296 possible number of the sequence. This number of the sequence does not increase by one with every number of sequences but by byte number of data transferred. Therefore, the MSS size is insignificant. Thus, it can be inferred that the maximum L value is representable by 2^32 ≈ 4.19 Gbytes.

b)  ceil(2^32 / 536) = 8,012,999

The segment number is 66 bytes of header joined to every segment to get a cumulative sum of 528,857,934 bytes of header. Therefore, overall number of bytes sent will be 2^32 + 528,857,934 =  4.824 × 10^9 bytes.  Thus, we can conclude that the total time taken to send the file will be 249 seconds over a 155~Mbps link.

8 0
2 years ago
Which of the following qualifies as a teamwork skill? A. Free associating B. Multitasking C. Listening D. Problem solving
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