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hichkok12 [17]
4 years ago
5

What are the x-intercepts of the graph of the function f(x) = x2 + 4x – 12?

Mathematics
2 answers:
hjlf4 years ago
6 0
The x-intercepts occur when f(x)=0

x^2+4x-12=0  factor

x^2-2x+6x-12=0

x(x-2)+6(x-2)=0

(x+6)(x-2)=0

x=-6 and 2  or specifically the points (-6,0) and (2, 0)
sukhopar [10]4 years ago
3 0

(x+6)(x-2)

x=2 and x=-6.

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yanalaym [24]
You know that y^2=4x so x=\dfrac{y^2}{4}.
Area of a shaded region is:

$A=\int\limits_0^k\dfrac{y^2}{4}\,dy=\frac{1}{4}\int\limits_0^ky^2\,dy=\frac{1}{4}\left[\frac{y^3}{3}\right]_0^k=\frac{1}{4}\left[\frac{k^3}{3}-\frac{0^3}{3}\right]=\frac{1}{4}\cdot\dfrac{k^3}{3}=\boxed{\frac{k^3}{12}}

so k:

\dfrac{k^3}{12}=\dfrac{9}{4}\\\\\\k^3=\dfrac{9\cdot12}{4}\\\\\\k^3=9\cdot3\\\\k^3=3^3\quad|\sqrt[3]{(\ldots)}\\\\\boxed{k=3}


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4 years ago
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3 0
3 years ago
Can someone help me
Phoenix [80]
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3 years ago
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mart [117]

Answer:

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Step-by-step explanation:

1199.28856995

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