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ohaa [14]
3 years ago
6

How do u solve the quadratic equation x^2-x-2?

Mathematics
1 answer:
Elena-2011 [213]3 years ago
6 0

Answer:

(x-2)(x+1)

Step-by-step explanation:

Factor!

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With a headwind a plane traveled 128 km in 2h. The return trip with a tail wind took 24 min less. Find the air speed of the plan
sertanlavr [38]

Based on the information given, it can be noted that the air speed that the plane has will be 71.1 km per hour.

The number of hours used for the return trip will be:

= 2 hours - 24 minutes.

= 1 hour 36 minutes.

= 1.6 hours.

Therefore, the speed of the air plane will be:

= (128 + 128) / (2 + 1.6)

= 256/3.6.

= 71.1 km per hour.

Learn more about speed on:

brainly.com/question/25860159

6 0
2 years ago
If you set your automobile's cruise control to travel at a speed of 57 miles per hour, how long will it take you (in hours) to d
Sati [7]
3 hours and 45 minutes
6 0
2 years ago
Write the equation of a line that passes through points (0,4) and (-2,-3) in slope intercept form
Otrada [13]

y=mx+b is the equation of a line;

m=slope , b= y-intercept

You can find the slope with this following equation: (y(2)-y(1))/(x(2)-x(1))

In this case the points are (0,4) and (-2,-3). The first set being (0,4) and the second (-2,-3). This means (0,4) can be expressed as (x(1),y(1)) and (-2,-3) expressed as (x(2),y(2)). Plugging these numbers into the slope equation gives us: (-3-4)/(-2-0) = -7/-2 = 7/2.

m= 7/2 ; so we have : y= (7/2)x+b

We are give a set of points which it passes through, we can simply plug them in:

4 = (7/2)(0)+b (0 is the x and 4 is the y)

We get 4 = 0 +b .... 4=b

our final equation is : y=(7/2)x+4

4 0
3 years ago
Solve pls branliest!
Shkiper50 [21]

Answer:

2004-(-185)=2189

-185+469=284

Step-by-step explanation:

I double checked them

5 0
2 years ago
Read 2 more answers
If, P(x,y) is a point on the unit circle determined by real number δ, then tanδ = what
Lisa [10]
\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
=\cfrac{y}{r}
=\cfrac{1}{csc(\theta)}
\\ \quad \\\\
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}
=\cfrac{x}{r}
=\cfrac{1}{sec(\theta)}
\\ \quad \\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
=\cfrac{y}{x}
=\cfrac{sin(\theta)}{cos(\theta)}

\bf cot(\theta)=\cfrac{adjacent}{opposite}
=\cfrac{x}{y}
=\cfrac{cos(\theta)}{sin(\theta)}
\\ \quad \\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
=\cfrac{r}{y}
=\cfrac{1}{sin(\theta)}
\\ \quad \\\\
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}
=\cfrac{r}{x}
=\cfrac{1}{cos(\theta)}\\\\
-------------------------------\\\\
P(x,y)\implies \delta\qquad tan(\delta)=\cfrac{y}{x}
5 0
3 years ago
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