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ira [324]
3 years ago
8

Simplify each of the following powers of i. I^22

Mathematics
2 answers:
katrin2010 [14]3 years ago
6 0

Answer:

-1 is the edge answer

Step-by-step explanation:

GaryK [48]3 years ago
3 0

Answer:

-1

Step-by-step explanation:

i^0 =1

i ^1 = i

i^2 =-1

i^3 = -i

It cycles through  by 4

so i^4 is back to 1

Take the power , divide by 4  and look to the chart for the remainder

If the remainder  is 0  then  i to that power is 1

                                1                                          i

                                2                                         -1

                                 3                                         -i


i^22

Take 22/4 = 5 remainder 2

The remainder is 2   so i^22 = -1


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Step-by-step explanation:

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Step-by-step explanation:

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Use the number line below, where RS = 9y +3, ST = 3y + 4, and RT = 17y - 33.
zavuch27 [327]

Answer:

R___S___T

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(17y-33) =( 9y+3)+(3y+4)

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<u>Or</u><u> </u><u>;</u> RT=RS+ST =75+28= 103

<h3><u>So</u><u>;</u></h3><h3>a. <u>Ans;</u> y=8</h3>

<h3>b. <u>Ans;</u> RS= 75 , ST = 28 , RT = 103</h3>

I hope I helped you^_^

4 0
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frosja888 [35]
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