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shtirl [24]
3 years ago
5

NEED HELP ASAP 70 POINTS

Mathematics
1 answer:
Tomtit [17]3 years ago
5 0

Answer:

x = 24 inches

Step-by-step explanation:

We can use similar triangles and proportions to solve.  Put the side of the small triangle over the side of the large triangle

5               8

---------- = -----------------

15                  x

Using cross products

5x = 15*8

5x = 120

Divide each side by 5

5x/5 = 120/5

x = 24


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Which expression plzzzz helpppppppp
lara31 [8.8K]
Answer is D

sum of constants = 8 + 4 = 12
sum of coefficients = 7 + 3 = 10

12 > 10  
7 0
3 years ago
How to find slope and writting a equation with tables
olga_2 [115]

Answer:The equation of a line is written as ​y=mx​+​b​, where the constant ​m​ is the slope of the line, and the ​b​ is the ​y​-intercept.

Step-by-step explanation:

3 0
2 years ago
Which plan to prove ∆ABD ≅ ∆CBD CANNOT be used based on the information in the diagram?
Kryger [21]

The plan that cannot be used to prove that the two triangles are congruent based in the given information is: b. ASA.

<h3>How to Prove Two Triangles are Congruent?</h3>

The following theorems can be used to prove that two triangles are congruent to each other:

  • SSS: This theorem proves that two triangles are congruent when there's enough information showing that they have three pairs of sides that are congruent to each other.
  • ASA: This theorem shows that of two corresponding angles of two triangles and a pair of included congruent sides are congruent to each other.
  • SAS: This theorem shows that if two triangles have two pairs of sides and a pair of included angle that are congruent, then both triangles are congruent to each other.

The two triangles only have a pair of corresponding congruent angles, while all three corresponding sides are shown to be congruent to each other.

This means that ASA which requires two pairs of congruent angles, cannot be used to prove that both triangles are congruent.

The answer is: b. ASA.

Learn more about congruent triangles on:

brainly.com/question/1675117

#SPJ1

5 0
1 year ago
Miki has 104 nickels and 88 dimes. She wants to divide her coins into groups where each group has the same number of nickels and
pochemuha

Given :

Miki has 104 nickels and 88 dimes.

She wants to divide her coins into groups where each group has the same number of nickels and the same number of dimes.

To Find :

Largest number of groups she can have .

Solution :

In the given question we need to find the largest number of groups she can have i.e we have to find the LCM of 104 and 88 .

Now , factorizing both of them , we get :

104=1\times 2\times 2\times 2\times 13

88=1\times 2\times 2\times 2\times 11

Form above , we can say that common factors are :

HCF=2\times 2\times 2=8

Therefore , the largest number of groups she can have is 8 .

Hence , this is the required solution .

6 0
3 years ago
Read 2 more answers
Find the measure of
koban [17]

Answer:

m∡GHI = 21°

Step-by-step explanation:

Since the lines are intersecting, GHI and JHK are opposite angles, so they are the same measure.

That means you can set them equal to each other

x + 7 = 3x - 21

x = 14

Now plug x into GHI

14 + 7 = 21

m∡GHI = 21°

7 0
3 years ago
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