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oksano4ka [1.4K]
3 years ago
9

Explain how to use a graph of the function f(x) to find f(3)​

Mathematics
2 answers:
fenix001 [56]3 years ago
8 0

Answer:

Just find the coordinate at the point where the x-coordinate is 3

Step-by-step explanation:

F(x) is just another term for Y. The variable of X is the value that you input into the f(x), which just stands for a function. Since the value that they asked for was 3, you know that they inputted the value of 3 as x. Just look where the coordinate at the point where the x-coordinate is 3 to find the answer.

elena-s [515]3 years ago
5 0

Answer:

Sample Response: For f(3), the input is 3 and you are looking for the output. To determine the function's value when x = 3, go to the value of 3 on the x-axis and then locate the graph for that value of x. Determine the value of y from the y-axis at that location on the graph.

Step-by-step explanation:

answer on edge2020

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A manufacturer is designing a flashlight. For the flashlight to emit a focused beam, the bulb needs to be on the central axis of
aalyn [17]
From the problem, the vertex = (0, 0) and the focus = (0, 3)
From the attached graphic, the equation can be expressed as:
(x -h)^2 = 4p (y -k)
where (h, k) are the (x, y) values of the vertex (0, 0)
The "p" value is the difference between the "y" value of the focus and the "y" value of the vertex.
p = 3 -0
p = 3
So, we form the equation
(x -0)^2 = 4 * 3 (y -0)
x^2 = 12y
To put this in proper quadratic equation form, we divide both sides by 12
y = x^2 / 12

Source:
http://www.1728.org/quadr4.htm




5 0
3 years ago
Help.It have answer choices​
amm1812
The answer is Impossible
6 0
3 years ago
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PLEASE HELO ASAP, 12 POINTS!!!
never [62]

Answer:b

Step-by-step explanation:l

3 0
3 years ago
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A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

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What is the total value of 245 $1 bills
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What do you mean... $245???
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