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3 years ago

Is 0.6 greater or less than 0.60

Mathematics

2 answers:

lys-0071 [83]3 years ago

7 0

It is the same. Even though you put a 0 in the end can't change the number

Nana76 [90]3 years ago

5 0

It is same because if u see there is 0 behind 0.6 but u can't see it so it is equal

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Find the general indefinite integral. (use c for the constant of integration. )

Vlada [557]

The indefinite integral will be $\int (7x^2+8x-2)dx=\dfrac{7x^3}{3}+4x^2-2x+C)$

<h3 /><h3>what is indefinite integral?</h3>

When we integrate any function without the limits then it will be an indefinite integral.

General Formulas and Concepts:

Integration Rule [Reverse Power Rule]:

$\int x^ndx=\dfrac{x^{n+1}}{n+1}}+C$

Integration Property [Multiplied Constant]:

$\int cf(x)dx=c\int f(x)dx$

Integration Property [Addition/Subtraction]:

$\int [f(x)\pmg(x)]dx=\int f(x)dx\pm \intg(x)dx$

[Integral] Rewrite [Integration Property - Addition/Subtraction]:

$\int (7x^2+8x-2)dx=\int 7x^2dx+\int 8xdx -\int 2dx$

[Integrals] Rewrite [Integration Property - Multiplied Constant]:

$\int (7x^2+8x-2)dx=7 \int x^2dx+ 8 \int xdx -2\int dx$

[Integrals] Reverse Power Rule:

$\int (7x^2+8x-2)dx= 7(\dfrac{x^3}{3})+8(\dfrac{x^2}{2})-2x+C$

Simplify:

$\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C$

So the indefinite integral will be $\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C$

To know more about indefinite integral follow

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7 0

2 years ago

Help is highly appreciated

grandymaker [24]

Answer:

Step-by-step explanation:

2-(-1\8)±-7\4 then

2 plus 1\8 plus -7\4

2 plus 1\8 plus -14\8

2 -13\8

2= 16/8

3\8?

3 0

3 years ago

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Ill i need to know is the fraction please

murzikaleks [220]

Answer:

6/10 i think

Step-by-step explanation:

625 divided by 15 is 41.6 so i'd be 40+1+6/10

6 0

3 years ago

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The x-intercept of the graph of f(x)= 3log(x-5)+2 is:

Mkey [24]

Your answers we equal to 22

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3 years ago

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Convert 3 over 8 to a decimal and tell whether it terminates or repeats.

Stels [109]

I think the answer is c

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