Answer:
Height(h) = 24in
Area = 204in²
Step-by-step explanation:
we would use the heron formula because we have all the sides to calulate the area
S = (A+B+C)/2 = (25 + 17 + 26)/2 = 68/2 = 34
area = √s(s-a)(s-b)(s-c) = √34(34-25)(34-17)(34-26) = √34(9)(17)(8) = √34x9x17x8 = √41616 = 204
area= (1/2)bh
204 = (1/2)bh b= 17, h =?
204 = (1/2)17h
204 x 2 = 17h
408 = 17h
h = 408/17 = 24in
Height(h) = 24in
Area = 204in²
Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.
1. x = ?
2. m∠MKL = ?
3. m∠JKL = ?
Answer/Step-by-step explanation:
Given:
m<JKM = 43,
m<MKL = (8x - 20),
m<JKL = (10x - 11).
Required:
1. Value of x
2. m<MKL
3. m<JKL
Solution:
1. Value of x:
m<JKL = m<MKL + m<JKM (angle addition postulate)
Therefore:

Solve for x


Subtract 8x from both sides


Add 11 to both sides


Divide both sides by 2


2. m<MKL = 8x - 20
Plug in the value of x
m<MKL = 8(17) - 20 = 136 - 20 = 116°
3. m<JKL = 10x - 11
m<JKL = 10(17) - 11 = 170 - 11 = 159°
Multiply the numerator and denominator by the whole number. you'll most likely get an improper fraction though.