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denis-greek [22]
3 years ago
14

Linnea's company's revenue in 20172017 is \dfrac{36}{25} 25 36 ? of its revenue in 20162016. What is Linnea's company's revenue

in 20172017 as a percent of its revenue in 20162016 ?
Mathematics
1 answer:
Anarel [89]3 years ago
4 0

Answer:

144%

Step-by-step explanation:

We are told that Linnea's company's revenue in 2017 is 36/25 of its revenue in 2016..

To find the Linnea's company's revenue in 2017 as a percent of its revenue in 2016, we will have to figure out 36 is what percent of 25.    

\text{Percent}=\frac{36}{25}\times 100  

\text{Percent}=36\times 4      

\text{Percent}=144  

Therefore, Linnea's company's revenue in 2017 is 144% of its revenue in 2017.

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Suppose a random sample of 50 college students are asked to measure the length of their right foot in centimeters. A 95% confide
hichkok12 [17]

Answer:

A  99% confidence interval  will be wider than a 95% confidence interval

Step-by-step explanation:

From the question we are told that

  The  95% confidence interval for for the mean foot length for students at the college is found to be 21.709 to 25.091 cm

Generally the width of a confidence interval is dependent on the margin of error.

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

From the above equation we see that

          E \ \  \alpha \ \   Z_{\frac{\alpha }{2} }

Here  Z_{\frac{\alpha }{2} }  is the critical value of the half of the level of significance and this value  increase as the confidence level increase

Now if a  99% confidence level is  used , it then means that the value of  

 Z_{\frac{\alpha }{2} }  will increase, this in turn will increase  the margin of error and in turn this will increase the width of the confidence interval

Hence a 99% confidence interval  will be wider than a 95% confidence interval

5 0
3 years ago
g In a one-tail hypothesis test where you reject H0 only in the lower tail, what is the p-value if Z STAT
zepelin [54]

Answer:

The P-value is 0.0166.

Step-by-step explanation:

<u>The complete question is:</u> In a​ one-tail hypothesis test where you reject H0 only in the lower ​tail, what is the p-value  if ZSTAT = -2.13.

We are given that the z-statistics value is -2.13 and we have to find the p-value.

Now, the p-value of the test statistics is given by the following condition;

                    P-value = P(Z < -2.13) = 1 - P(Z \leq 2.13)

                                  = 1 - 0.9834 = <u>0.0166</u>

Assuming that the level of significance is 0.10 or 10%.

The decision rule for rejecting the null hypothesis based on p-value is given by;

  • If the P-value of the test statistics is less than the level of significance, then we have sufficient evidence to reject the null hypothesis.
  • If the P-value of the test statistics is more than the level of significance, then we have insufficient evidence to reject the null hypothesis.

Here, the P-value is more than the level of significance as 0.0166 > 0.10, so we have insufficient evidence to reject the null hypothesis, so we fail to reject the null hypothesis.

3 0
3 years ago
Solve the two-step equation.<br> - 2/3 x - 21/4 = 27/4
Natasha_Volkova [10]

Answer:

x = -18

I hope this helps!

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3 years ago
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Calculate limits x&gt;-infinity<br> -2x^5-3x+1
Lera25 [3.4K]

Given:

The limit problem is:

\lim_{x\to -\infty}(-2x^5-3x+1)

To find:

The value of the given limit problem.

Solution:

We have,

\lim_{x\to -\infty}(-2x^5-3x+1)

In the function -2x^5-3x+1, the degree of the polynomial is 5, which is an odd number and the leading coefficient is -2, which is a negative number.

So, the function approaches to positive infinity as x approaches to negative infinity.

\lim_{x\to -\infty}(-2x^5-3x+1)=\infty

Therefore, \lim_{x\to -\infty}(-2x^5-3x+1)=\infty.

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A plan for an executive travelers' club has been developed by an airline on the premise that 5% of its current customers would q
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Answer:

Step-by-step explanation:

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