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2 years ago

6

The average score on the statistics final exam was 85 and the standard deviation was 2.5 . Chris scored a 95 . Chris scored high

er than what percent of his class?

1 answer:

Anna007 [38]2 years ago

7 0

Answer:

55%

Step-by-step explanation:

its honestly just a guess

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3 years ago

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3 years ago

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1 year ago

Use the net as an aid to compute the surface area (rounded to the nearest integer) of the triangular pyramid with an equilateral

aleksandrvk [35]

Answer:

Correct answer is $C)\ 254\ m^{2}$

Step-by-step explanation:

As per the given diagram, we know the following details:

Height of the triangular pyramid is <em>14m</em>.

<em>Side of base</em> = <em>10m </em>

Height of Triangular base = <em>8.7m</em>

Formula for <em>surface area of triangular pyramid</em>:

$\text{Area = Area of Triangular base + 3 }\times\text{Area of side triangle}$

(Triangular base is shown in the dotted lines in the question figure.

The other 3 triangles are the side triangles.)

We know that,

$\text{Area of a triangle = }\dfrac{1}{2} \times \text{Base} \times \text{Height}$

$\Rightarrow \text{Required Surface Area = } \dfrac{1}{2} \times 8.7 \times 10 + 3 \times \dfrac{1}{2} \times 14 \times 10\\\Rightarrow \dfrac{1}{2}\times (87 + 3 \times 140)\\\Rightarrow \dfrac{1}{2}\times (87 + 420)\\\Rightarrow \dfrac{1}{2} \times 507\\$\approx$ 254 m^{2}$

Hence correct answer is $C)\ 254\ m^{2}$ .

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2 years ago