Answer:
The change in temperature per minute for the sample, dT/dt is 71.
°C/min
Step-by-step explanation:
The given parameters of the question are;
The specific heat capacity for glass, dQ/dT = 0.18 (kcal/°C)
The heat transfer rate for 1 kg of glass at 20.0 °C, dQ/dt = 12.9 kcal/min
Given that both dQ/dT and dQ/dt are known, we have;


Therefore, we get;


For the sample, we have the change in temperature per minute, dT/dt, presented as follows;

Answer:
The sum of two numbers is 240. The larger number is 6 less than twice the smaller. Find the numbers.
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Let the smaller be "x" ; Larger is "2x-6"
EQUATION:
x + 2x-6 = 240
3x= 246
x = 82 (smaller)
2x-6 = 158 (larger)
Step-by-step explanation:
Answer:
m∠QTR = 98°
Step-by-step explanation:
From the picture attached,
Radii of the circle are TQ and TR measuring equal lengths.
Therefore, ΔTQR is a isosceles triangle.
Opposite angles of the equal sides will be equal in measure.
m∠RQT = m∠TRQ = 41°
By angle sum theorem,
m∠RQT + m∠TRQ + m∠QTR = 180°
41° + 41° + m∠QTR = 180°
m∠QTR = 180° - 82°
= 98°
Therefore, m∠QTR = 98°