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Lesechka [4]
4 years ago
6

What is the perimeter of triangle ABC?

Mathematics
1 answer:
ddd [48]4 years ago
8 0

Answer: 24 units.

Step-by-step explanation: Count out how many units long AB is. AB goes from -3 to 3, for a length of 6 units.

Count out how long AC is. AC goes from 4 to -4, for a length of 8 units.

To find BC, use the Pythgorean theorem (a^2+b^2=c^2). 8^2 is 64, and 6^2 is 36. Add 64 and 36 to get 100. Then find the square root of 100, which is 10.

Add all the lengths. 6+8+10=24.

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What is the value of x?<br> 160°<br> x =<br> 519
forsale [732]

Answer:

x = 58

Step-by-step explanation:

Angle Formed by Two Secants = 1/2(difference of Intercepted Arcs)

51 =1/2 (160-x)

Multiply each side by 2

102 = 160-x

Subtract 160 from each side

102-160 = -x

-58 = -x

Multiply by -1

58 =x

6 0
3 years ago
Read 2 more answers
Find the solutions to the system; y=x^2-3x-1 and y=8x-1
Ne4ueva [31]
Find the solutions to the system; y=x^2-3x-1 and y=8x-1

8 0
3 years ago
What is the square root of 37.
Norma-Jean [14]
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7 0
4 years ago
WICH EQUATION CAN BE USED TO FIND THE AREA OF THE RECTANGLE
allsm [11]

Answer:

A = L x W

Step-by-step explanation:

<em>Because the equation of a rectangle is understood the best way to help you understand the equation of l*w is to break down the definiton of a rectangle.</em>

Defining a rectangle:

The rectangle is a quadrillateral with two parallel sets of sides which are perpendicular to each other.

Understanding it:

Now let's look at a rectangle

Let's say the length is 5 units and the width is 10 units.

To find that meat in between we understand that 5 units of length extends through all 10 units of the width. This means 5 is carried out for 10 units meaning that 5x10 is the area of the Rectangle. As such the area would be 50

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5 0
3 years ago
What expression gives the distance between the points 5,1 and 9,-6
notka56 [123]

<u>Answer:</u>

Distance between the points 5,1 and 9,-6 is 8.0622

<u>Explanation:</u>

Given points = (5,1) and (9,-6)

The square root of this is the distance between the points Distance  can be calculated

from the expression=   \sqrt{(x 2-x 1)^{2}+(y 2-y 1)^{2}}

=   \sqrt{(9-5)^{2}+(-6-1)^{2}}

=     \sqrt{(4)^{2}+(-7)^{2}}

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Distance (d) from given points = (5,1) and (9,-6) is  8.0622.

3 0
3 years ago
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