Triangle ACB and triangle ABD share one side AB. This means they have one side that is congruent; side AB
Angle ABD = Angle ABC
Angle BAC = Angle BAD
The pair of angles that are equal lie on the side AB
Hence, triangle ABC and triangle ABD are congruent by Angle-Side-Angle (ASA)
Answer: Second option
Answer:
x>3
Step-by-step explanation:
We are given with the inequation 3(8-4x) < 6(x - 5)
Dividing both sides in the above in equation by 3 we get
(8-4x)<2(x-5)
Distributing 2 over (x-5)
(8-4x)<2x-10
8-4x<2x-10
adding 10 and 4x on both hand sides we get
8+10<2x+4x
18<6x
Dividing both sides by 6 we get
3<x
Hence the solution to the given in equation is x>3
Answer:
Solution given:
<6+24=180[co- interior angle]
<6=180-24=156°
<6=156°
<span>25x2 = 16
x^2 = 16/25
</span>x^2 = 4^2/5^2
<span>x = 4/5
</span>