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3 years ago

Three numbers are in the ratio 2:3:5. If the sum of their cubes is 1280.Find the three numbers.

Mathematics

1 answer:

Charra [1.4K]3 years ago

3 0

Answer:256,384,640

Step-by-step explanation:

Take the ration sum 2x+3x+5x=1280

When we add we get 10x=1280

Then find x by. x=1280/10=128

Then substitute this x value to the ratios 2x=2*128 =256

3x=3*128=384

5x=5*128=640

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2 years ago

Read 2 more answers

Select two polynomials that have a sum of 16n^3+13n^2+7n-10 A. 8n^3 - 5n +11n^2 - 5 B. 7n^2 + 8n - n^3 + 2 C. 15n^2 - 10n + 3n^3

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Answer:

Step-by-step explanation:

We have the polynomial

$16n^3+13n^2+7n-10$ ( 1 )

To solve this problem we have to take into account that only we can sum term with the same order in the variable. We have the polynomials

$8n_{3}-5n+11n^{2}-5\\7n^2 + 8n - n^3 + 2\\15n^2 - 10n + 3n^3 - 4\\2n^2 + 12n - 5 + 8n^3$

we can note (by summing term by term) that only the sum of the first and the fourth equation correspond to the given polynomial ( 1 ) of the problem. If we organize these polynomials (that is, write the equation down in a form where higher order appears first ) we have

$8n^3 +11n^2 - 5n - 5\\ 8n^3+2n^2 + 12n - 5\\$

and if we sum we obtain

$16n^3+13n^2+7n-10$

that is what we was looking for

I hope this is useful for you

regards

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2 years ago