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3 years ago

12

The 24-hour time is 14:00. Find the equivalent 12-hour time. Show all work.

1 answer:

Alexxandr [17]3 years ago

7 0

It's 2:00 pm.
12:00 is noon, and since 14 is 2 hours more, I just figured it out. Here are some other answers.

13:00- 1 pm
14:00- 2 pm
15:00- 3 pm
16:00- 4 pm
17:00- 5 pm
18:00- 6 pm
19:00 7 pm
20:00 8 pm
21:00 9 pm
22:00- 10 pm
23:00 is 11 pm
24:00 is midnight
Any of those with numbers after that is the same hour with different minutes, for example 20:22 is 8:22 pm. Hope I helped.

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Use a graphing calculator to solve the equation -3 cost= 1 in the interval from . Round to the nearest hundredth.

RSB [31]

In place of t, or theta, I'm going to utilize x instead. So the equation is -3*cos(x) = 1. Get everything to one side and we have -3*cos(x)-1 = 0

Let f(x) = -3*cos(x)-1. The goal is to find the root of f(x) in the interval [0, 2pi]

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A = (1.91, 0)
B = (4.37, 0)

So the two solutions for theta are
theta = 1.91 radians
theta = 4.37 radians

8 0

3 years ago

10. 2x + 7y = 1<br> 2x - 4y = 12<br> Solve for y

adoni [48]

Answer:

The solution for y = -1.

Step-by-step explanation:

Given:

$2x\ +\ 7y\ =\ 1$ ....(1)

$2x\ -\ 4y\ =\ 12$ ....(2)

So, to solve for y, first we solve for x in equation (2):

$2x-4y=12$

⇒ $2x=12+4y$

Dividing both sides by 2,

⇒ $x=6+2y$

Now, substituting the value of x in equation (1):

$2x+7y=1$

⇒ $2(6+2y)+7y=1$

⇒ $12+4y+7y=1$

⇒ $12+11y=1$

⇒ $11y=1-12$

⇒ $11y=-11$

Dividing both sides by 11,

⇒ $y=-1$

Therefore, the solution for y = -1.

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3 years ago

The graph below shows the relationship between test grades and shoe sizes of the students in Dexter's class.

FrozenT [24]

Yeah that is correct so yeah you are right I don’t know any more information that I could give you but I’m pretty sure you just said it right so yeah

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3 years ago

Read 2 more answers

Find the complex fourth roots \[-\sqrt{3}+\iota \] in polar form.

____ [38]

Let $z=-\sqrt3+i$ . Then

$|z|=\sqrt{(-\sqrt3)^2+1^2}=2$

$z$ lies in the second quadrant, so

$\arg z=\pi+\tan^{-1}\left(-\dfrac1{\sqrt3}\right)=\dfrac{5\pi}6$

So we have

$z=2e^{i5\pi/6}$

and the fourth roots of $z$ are

$2^{1/4}e^{i(5\pi/6+k\pi)/4}$

where $k\in\{0,1,2,3\}$ . In particular, they are

$2^{1/4}e^{i(5\pi/6)/4}=2^{1/4}e^{i5\pi/24}$

$2^{1/4}e^{i(5\pi/6+2\pi)/4}=2^{1/4}e^{i17\pi/24}$

$2^{1/4}e^{i(5\pi/6+4\pi)/4}=2^{1/4}e^{i29\pi/24}$

$2^{1/4}e^{i(5\pi/6+6\pi)/4}=2^{1/4}e^{i41\pi/24}$

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3 years ago

What would the x and y intercept for the following question? 5x+10y=20

Setler79 [48]

Answer:

y= 1/2x+2

y int is 2

x int is -2

Step-by-step explanation:

plug in 0 for y int

set the equation equal to 0 for x int

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3 years ago