What we need to do first, is to write the equation of the line through points A and B.
the slope of the line through A(3, 7) and B(-4, 9) is
the equation of the line is :
C(a, 1) is on this line so it must satisfy the equation:
Answer:
a.-(p-1)(p-6)
b.(a+2)(a+2-b)
c 3(b-2)^2
d.(c-5)(1+2x)
Step-by-step explanation:
Answer:
9.27•10^5
Step-by-step explanation:
Answer:
y = -3 + 6ˣ
Step-by-step explanation:
-3 is the lowest it goes, and the more you increase the base, the more it its stretch will become. Now, although it passes through -2, we are not dealing with y-intercept here because this is NOT a linear function. This is called a horizontal asymptote. This is an exponential function, from the parent function of <em>y</em><em> </em><em>=</em><em> </em><em>abˣ</em><em>,</em><em> </em>if I can recall correctly. Anyway, you understand?
Answer:
Step-by-step explanation:
From the given information, the symmetric equations for the line pass through(4, -5, 2) i.e (
) and are parallel to 
The parallel vector to the line i + zj+k = ai + bj + ck
Hence, the equation for the line is :
x = 4 + t
y = -5 + 2t
z = 2 + t
Thus, x, y, z = ( 4+t, -5+2t, 2+t )
The symmetric equation can now be as follows:
∴
