(3a^2-3b)(2a^2+3b) find the product
1 answer:
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Answer:
x+6
Step-by-step explanation:
Let's see if the numerator is factorable.
Since the coefficient of x^2 is 1 (a=1), all you have to do is find two numbers that multiply to be -6 (c) and add up to be 5 (b).
Those numbers are 6 and -1.
So the factored form of the numerator is (x+6)(x-1)
So when you divide (x+6)(x-1) by (x-1) you get (x+6) because (x-1)/(x-1)=1 for number x except x=1 (since that would lead to division by 0).
Anyways, this is what I'm saying:
C: 4 is the right answer
Step-by-step explanation:
Given
a1 = -3
a15 = 53
We know that explicit formula for the arithmetic sequence is:
For the 15th, term it will be
Adding 3 on both sides
Dividing both sides by 14
Hence,
C: 4 is the right answer
Keywords: Arithmetic sequence, Common Difference
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