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neonofarm [45]
2 years ago
5

The first term of an arithmetic sequence is -3 and the fifteenth term is 53. What is the common difference of the sequence?

Mathematics
1 answer:
Maru [420]2 years ago
4 0

C: 4 is the right answer

Step-by-step explanation:

Given

a1 = -3

a15 = 53

We know that explicit formula for the arithmetic sequence is:

a_n=a_1+(n-1)d

For the 15th, term it will be

a_{15}=-3+(15-1)d\\53=-3+14d

Adding 3 on both sides

53+3 = -3+3 + 14d\\56 = 14d

Dividing both sides by 14

\frac{56}{14}=\frac{14d}{14}\\d=4

Hence,

C: 4 is the right answer

Keywords: Arithmetic sequence, Common Difference

Learn more about arithmetic sequence at:

  • brainly.com/question/12896802
  • brainly.com/question/12973601

#LearnwithBrainly

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You buy a new laptop for $300$300. The sales tax is 6%6%. What is the total cost for the laptop including the sales tax?
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Answer:

Cost Including tax would be $318

Step-by-step explanation:

Given:

Price of laptop = $300

Sales tax = 6% of price

To Find:

Cost with tax = ?

Solution:

Cost with tax = Price of laptop + Value of tax

We have to find the value of tax

Value of tax = 6% of Price

putting the value

Value of tax = 6 % * $300

                     =\frac{6}{100}*300

                     = $18

Now Cost with tax = Price of laptop + Value of tax

Putting in the value

Cost with tax = 300 + 18

                      = $318

So Cost Including tax would be $318


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How many solutions does the equation 3x-2(x+10)=x-20 ​
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Step-by-step explanation:

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Find the product.<br> (y - 2bs^2) (y + 3bs^2)<br> Enter the correct answer.
Vikentia [17]

Answer:

y² + bs²y - 6b²s⁴

General Formulas and Concepts:

  • Expand by FOIL (First Outside Inside Last)
  • Exponent Power Rule: (b^m)^n=b^{mn}

Step-by-step explanation:

<u>Step 1: Define expression</u>

(y - 2bs²)(y + 3bs²)

<u>Step 2: FOIL</u>

  1. First:               y · y = y²
  2. Outside:         y · 3bs² = 3bs²y
  3. Inside:            -2bs² · y = -2bs²y
  4. Last:               -2bs² · 3bs² = -6b²s⁴

<u>Step 3: Simplify</u>

  1. Combine:                         y² + 3bs²y - 2bs²y - 6b²s⁴
  2. Combine like terms:        y² + bs²y - 6b²s⁴
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