Answer:
The magnitude of the boat's velocity is 5.66 m/s
Step-by-step explanation:
Given;
Radius of curvature of the circular path, r = 40 m
speed of the boat, v = 0.8 t m/s
The magnitude of the boat's velocity when it has traveled 20 m is ?
a = dv / dt,
v = 0.8 t (differentiate with respect to t)
dv / dt = 0.8 = a
thus, a = 0.8 m/s²
If the boat starts from rest, initial velocity, u = 0
Apply kinematic equation, to solve for the boat velocity at 20 m
v² = u² + 2as
v² = 0 + 2 x 0.8 x 20
v² = 0 + 32
v² = 32
v = √32
v = 5.66 m/s
Therefore, the magnitude of the boat's velocity when it has traveled 20 m is 5.66 m/s
