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castortr0y [4]
3 years ago
9

Find the value of X.

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
8 0

Answer:

A. 12

Step-by-step explanation:

TU and CV are two chords of the circle that intersects at point w.

Thus,

x*3 = 9*4 (two intersecting chords theorem)

Solve for x

3x = 36

Divide both sides by 3

\frac{3x}{3} = \frac{36}{3}

x = 12

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A frequency table of grades has five classes (A, B, C, D,F) with frequencies of 4, 10, 17, 6, and respectively. Using percentage
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We have the frequencies for each of the grades. We can estimate the number of students graded by adding all those frequencies. Let's call N the total number of grades:

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We have then a total number of grades of 39.

The corresponding relative frequency for a grade is the ratio of the frequency to the total number of "samples", 39 in this case.

Then, for grade A, the relative frequency (RF) will be:

RF_A=\frac{4}{39}\approx0.10256\approx10.26\text{ \%}

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Now, to complete the table we do the same for the other frequencies:

For grade B:

RF_B=\frac{10}{39}\approx0.2564\approx25.64\text{ \%}

For grade C:

RF_C=\frac{17}{39}\approx0.4359\approx43.59\text{ \%}

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1 year ago
Of 450 college students, 110 are enrolled in math, 205 are enrolled in English, and 50 are enrolled in both. If a student is sel
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Answer:

Step-by-step explanation:

Given that Of 450 college students, 110 are enrolled in math, 205 are enrolled in English, and 50 are enrolled in both. If a student is selected at random

the probability

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(b) The student is enrolled in English.=\frac{205}{450} =0.456\\

(c) The student is enrolled in both.=\frac{50}{450} =0.111\\

(d) The student is enrolled in mathematics or English.=\frac{110+205-50}{450} =0.589\\

(e) The student is enrolled in English but not in mathematics.

=\frac{205-50}{450} =0.344\\

(f) The student is not enrolled in English or is enrolled in mathematics.

=\frac{450-205+110}{450} =0.7889\\

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(1) 3x + 9 and 5x + 15​
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Answer:

(1)3(x+3)

(2)5(x+3)

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