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4 years ago

Y- 7 = -4How do I solve this question

Mathematics

2 answers:

yan [13]4 years ago

6 0

Answer

y=3

Step-by-step explanation:

Add 7 to both sides of the equation since 7 is being subtracted (making it a negative)

Adding 7 to -4 equals 3

ziro4ka [17]4 years ago

3 0

Answer:

Let me know if you can't read it

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4 years ago

What are the solutions to the quadratic equation (5y+6)2=24

yulyashka [42]

The value of y is, $y=\frac{2\sqrt{6}-6}{5},\:y=\frac{-2\sqrt{6}-6}{5}$

We have given that,

$\left(5y+6\right)^2=24$

We have to determine the value of y,

<h3>What is the formula for the quadratic equation?</h3>

$\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

Therefore,we get

$5y+6=\sqrt{24}$

$5y+6=2\sqrt{6}$

$\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}$

$5y+6-6=2\sqrt{6}-6$

$5y=2\sqrt{6}-6$

$\frac{5y}{5}=\frac{2\sqrt{6}}{5}-\frac{6}{5}$

$y=\frac{2\sqrt{6}-6}{5}$

$y=\frac{2\sqrt{6}-6}{5},\:y=\frac{-2\sqrt{6}-6}{5}$

Therefore the value of y is,

$y=\frac{2\sqrt{6}-6}{5},\:y=\frac{-2\sqrt{6}-6}{5}$

To learn more about the quadratic equation visit:

brainly.com/question/1214333

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3 years ago

Can someone help me ?

antoniya [11.8K]

Answer:

AC is four times longer than DF

Step-by-step explanation:

AC is the diameter of the circle E and DE is the radius of the circle E

AC = 2 x DE

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DE = 2 x DF

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3 years ago

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Y- 7 = -4How do I solve this question​

Y- 7 = -4How do I solve this question