Answer:
232°
Step-by-step explanation:
There are a couple of ways to find the desired direction. Perhaps the most straightforward is to add up the coordinates of the travel vectors.
30∠270° +50∠210° = 30(cos(270°), sin(270°)) +50(cos(210°), sin(210°))
= (0, -30) +(-43.301, -25) = (-43.301, -55)
Then the angle from port is ...
arctan(-55/-43.301) ≈ 231.79° . . . . . . . 3rd quadrant angle
The bearing of the ship from port is about 232°.
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<em>Comment on the problem statement</em>
The term "knot" is conventionally used to indicate a measure of speed (nautical mile per hour), not distance. It is derived from the use of a knotted rope to estimate speed. Knots on the rope were typically 47 ft 3 inches apart. As a measure of distance 30 knots is about 1417.5 feet.
Answer:
m∡GHI = 21°
Step-by-step explanation:
Since the lines are intersecting, GHI and JHK are opposite angles, so they are the same measure.
That means you can set them equal to each other
x + 7 = 3x - 21
x = 14
Now plug x into GHI
14 + 7 = 21
m∡GHI = 21°
A + E + N = 122
E = 2N
A = 7 + E....A = 7 + 2N
(7 + 2N) + 2N + N = 122
5N + 7 = 122
5N = 122 - 7
5N = 115
N = 115/5
N = 23 <== North America
E = 2N
E = 2(23)
E = 46 <== Europe
A = 7 + E
A = 7 + 46
A = 53 <=== Africa
Answer:
x ≈ 18
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Trigonometry</u>
Law of Cosines: a^2 = b^2 + c^2 - 2(b)(c)cosA
- a is a side length
- b is a side length
- c is a side length
- A is an angle corresponding with side a
Step-by-step explanation:
<u>Step 1: Define</u>
a = x
A = 30°
b = 16
c = 30
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute: x² = 16² + 30² - 2(16)(30)cos30°
- Exponents: x² = 256 + 900 -2(16)(30)cos30°
- Evaluate: x² = 256 + 900 -2(16)(30)(√3/2)
- Multiply: x² = 256 + 900 - 480√3
- Add: x² = 1156 - 480√3
- Subtract: x² = 324.616
- Isolate <em>x</em>: x = √324.616
- Evaluate: x = 18.0171
- Round: x ≈ 18
