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zepelin [54]
3 years ago
6

Quincy uses the quadratic formula to solve for the values of x in a quadratic equation. He finds the solution, in simplest radic

al form, to be x = .
Which best describes how many real number solutions the equation has?

Zero, because the discriminant is negative. 

Zero, because the discriminant is not a perfect square.

One, because the negative and the minus cancel each other out.

Two, because of the ± symbol.
Mathematics
2 answers:
topjm [15]3 years ago
9 0

Answer:zero because the discriminant is not a perfect square

Step-by-step explanation:

Drupady [299]3 years ago
5 0

Answer:

zero because the discriminant is not a perfect square

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Ivan
Answers:
a. Given
b. Transitive property of congruence
c. Vertical angles are congruent
d. Transitive property of congruence

Let me know if you need any clarification as to how I got those answers. They should be self-explanatory but I'm happy to clarify further if needed. 

5 0
3 years ago
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How many solutions are there to the equation below?
bezimeni [28]

A square root cannot be equl to a negative.


answer: C. 0

6 0
2 years ago
Use the distributive property to remove the parenthesis<br> (v+12)10
serg [7]
The distributive property means to distribute the number being multiplied by the numbers in the parentheses.
In this case, (v+12) is being multiplied by 10.
To solve this, you simply have to multiply 10 by each term inside the parentheses.
That means it would be (v•10)+(12•10).
(v•10) is equal to 10v, since v is the variable and we don't know its value.
(12•10) is equal to 120.
So by using the distributive property we can find that (v+12)10 = 10v+120.
6 0
3 years ago
Please help . I’ll mark you as brainliest if correct!!!!!!
STatiana [176]

Answer:

3 are mushed

Step-by-step explanation:

You have 12 tomatoes

All but 9 get mushed

Total tomatoes = mushed + non mushed

12 = mushed +9

Subtract 9 from each side

12-9 = mushed+9-9

12-9 = mushed

3 = mushed

7 0
3 years ago
Read 2 more answers
Find the roots of the equation<br> x ^ 2 + 3x-8 ^ -14 = 0 with three precision digits
scoray [572]

Answer:

Step-by-step explanation:

Given quadratic equation:

x^{2} + 3x - 8^{- 14} = 0

The solution of the given quadratic eqn is given by using Sri Dharacharya formula:

x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}

The above solution is for the quadratic equation of the form:

ax^{2} + bx + c = 0  

x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}

From the given eqn

a = 1

b = 3

c = - 8^{- 14}

Now, using the above values in the formula mentioned above:

x_{1, 1'} = \frac{- 3 \pm \sqrt{3^{2} - 4(1)(- 8^{- 14})}}{2(1)}

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})})

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})} - 3)

Now, Rationalizing the above eqn:

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(- 8^{- 14})} - 3)\times (\frac{\sqrt{9 - 4(- 8^{- 14})} + 3}{\sqrt{9 - 4(- 8^{- 14})} + 3}

x_{1, 1'} = \frac{1}{2}.\frac{(\pm {9 - 4(- 8^{- 14})^{2}} - 3^{2})}{\sqrt{9 - 4(- 8^{- 14})} + 3}

Solving the above eqn:

x_{1, 1'} = \frac{2\times 8^{- 14}}{\sqrt{9 + 4\times 8^{-14}} + 3}

Solving with the help of caculator:

x_{1, 1'} = \frac{2\times 2.27\times 10^{- 14}}{\sqrt{9 + 42.27\times 10^{- 14}} + 3}

The precise value upto three decimal places comes out to be:

x_{1, 1'} = 0.758\times 10^{- 14}

5 0
3 years ago
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