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NARA [144]
3 years ago
9

Determine whether the equation represents a direct variation. If it does, find the constant of variation. -12x=6y

Mathematics
2 answers:
bazaltina [42]3 years ago
7 0

Answer:

The equation observes direct proportionality.

Step-by-step explanation:

The condition of direct proportionality follows to this expression:

y = k \cdot x

Where k is the constant of proportionality.

It is easy to conclude that equation observes the criterion of direct proportionality after some algebraic handling:

-12\cdot x = 6\cdot y

y = -2\cdot x

The constant of the proportionality is -2.

yawa3891 [41]3 years ago
6 0

For direct variation  we need <u>y  = Kx  ( where K is constant ) </u>

Direct variation :-  Two variable in  relationship when they are constant multiple with each other.{ one element proportional to other like r is direct proportional to Y

r  = K(y) k is constant

we have given equation  :-     -12 x = 6y

                                                  y    =  -12 x /6

                                                   y =  -2x

this is in the form of y = kx     (   constant of variation K =  -2 )

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drek231 [11]

Answer:

1) The height of the ball from 0 to 5  seconds are;

At t = 0 second, height = 2

At t = 1 second, height h = 22.1

At t = 2 seconds, height h = 32.4

At t = 3 seconds, height h = 32.9

At t = 4 seconds, height h = 23.6

At t = 5 seconds, height h = 4.5

2)  The correct option is;

D. -16·t² + 25·t + 1

Step-by-step explanation:

1) The equation of motion of the ball is given as follows;

H(t) = -4.9·t² + 25·t + 2

The height of the ball from 0 to 5 seconds are;

H(0) = -4.9×(0)² + 25×(0) + 2 = 2

H(1) = -4.9×(1)² + 25×(1) + 2 = 22.1

H(2) = -4.9×(2)² + 25×(2) + 2 = 32.4

H(3) = -4.9×(3)² + 25×(3) + 2 = 32.9

H(4) = -4.9×(4)² + 25×(4) + 2 = 23.6

H(5) = -4.9×(5)² + 25×(5) + 2 = 4.5

Therefore, we have;

The height of the ball are

At t = 0 second, height = 2

At t = 1 second, height h = 22.1

At t = 2 seconds, height h = 32.4

At t = 3 seconds, height h = 32.9

At t = 4 seconds, height h = 23.6

At t = 5 seconds, height h = 4.5

2) Given that the equation of the ball is that of a projectile motion, such as follows;

h = h₀ + v₀·sin(θ₀)·t - 1/2·g·t² which is equivalent to h = -1/2·g·t²+ h₀+v₀·sin(θ₀)·t

it is best represented by the quadratic equation of an upside down parabola which is option D. -16·t² + 25·t + 1

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alexdok [17]
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Answer:

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