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scZoUnD [109]
3 years ago
13

Pythagorean Theorem Comic Strip Mini Project (It's do in 3 hours)

Mathematics
1 answer:
MrRissso [65]3 years ago
8 0

Answer:

Ok I can give you scripts

Ill label the panel with (number) also the characters are below

triangle, hypotnuse, a, billy

1) Trinagle: I’m missing a side and I got a replacement but I forgot what it was and now its all messed up (insert sad face)

Bilily: Hey I can help with that, we can use soemthing call the Pythagorean Theorem!

2) Triangle: what is that?

Billy: *explains Pythagorean  theorem*

3) Triangle: Ahh, I have my hypotnuse and 1 side.

Hypotnuse: Yes I’m exact 5 inches

Side A: And I’m exactly 3 inches

4) Billy: So we can use the Pythagorean theorem by

3^2+b^2=5^2

5) Triangle: So i solve for B and thats it!

6) Triangle: I got it, Its 4 inches, thank you so much!!!

Billy: No problem

hypotenuse: Yes, and triangle

7) Triangle: yes?

hypotnuse: What happened to you and circle, weren’t you guys engaged?

8) Triangle: nah, he was pointless.

*end pannel with corny joke and you’d get extra credit :)*

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A) The center of gravity of the two joined beams is;

<u><em>(x, y) = (25/44), (19/88)</em></u>

B) The gravitational torque on the joined beams about an axis through the corner is;

<u><em>τ = 245 N.m</em></u>

We are given;

Mass of vertical beam; m₂ = 19 kg

Mass of horizontal beam, m₁ = 25 kg

Length of horizontal beam; L₁ = 2 m

Length of vertical beam; L₂ = 1 m

A) Formula for center of gravity of the two joined beams is;

(x, y) = [(m₁x₁ + m₂x₂)/(m₁ + m₂)],  [(m₁y₁ + m₂y₂)/(m₁ + m₂)]

Where;

(x₁, y₁) is the <em>center of gravity</em> on the <em>horizontal beam</em>

(x₂, y₂) is the <em>center of gravity</em> on the <em>vertical beam</em>

(x₁, y₁) = (L₁/2, 0)

Plugging in the relevant values gives;

(x₁, y₁) = (2/2, 0)

(x₁, y₁) = (1, 0)

(x₂, y₂) = (0, L₂/2)

Plugging in the relevant values gives;

(x₂, y₂) = (0, 1/2)

(x₂, y₂) = (0, 0.5)

Thus, center of gravity of the 2 joined beams is;

(x, y) = [((25 × 1) + (19 × 0))/(25 + 19)],  [((25 × 0)  + (19 × 0.5)))/(25 + 19)]

(x, y) = (25/44), (19/88)

B) Formula for the gravitational torque on the joined beams about an axis through the corner is given as;

τ = (m₁g)x₁ + (m₂g)x₂

Plugging in the relevant values;

τ = (25 × 9.8)1 + (19 × 9.8)0

τ = 245 N.m

Read more at; brainly.com/question/14825257

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Answer:

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