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4 years ago

Will someone come and help me with this math please?

Mathematics

1 answer:

Vilka [71]4 years ago

4 0

The correct answer is (70,50) as it’s proportional to the line because it crosses the point (45,30)

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Expanding brackets (2x + 4)(x - 6)

Natalija [7]

Answer:

=2x²-8x-24 is the answer

Step-by-step explanation:

=(2x+4)(x-6)

opening brackets by multiplying

=2x(x-6)+4(x-6)

=2x²-12x+4x-24

adding like terms

=2x²-8x-24

i hope this will help you :)

5 0

3 years ago

Read 2 more answers

A video game randomly chooses your car color and type. The probability of

Dennis_Churaev [7]

Maybe it is A i’m not 100 percent sure though

8 0

3 years ago

Describe the graph of the solution to the inequality 8x + 17 ≥ 137

ra1l [238]

Answer:

Simplifying

8x + 17 = 137

Reorder the terms:

17 + 8x = 137

Solving

17 + 8x = 137

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-17' to each side of the equation.

17 + -17 + 8x = 137 + -17

Combine like terms: 17 + -17 = 0

0 + 8x = 137 + -17

8x = 137 + -17

Combine like terms: 137 + -17 = 120

8x = 120

Divide each side by '8'.

x = 15

Simplifying

x = 15

6 0

3 years ago

A magazine conducts an annual survey in which readers rate their favorite cruise ship. All ships are rated on a 100-point scale,

Lyrx [107]

Answer:

a) The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =85.82-81.90=3.92$

b) $SE=\sqrt{(\frac{4.55^2}{35}+\frac{3.97^2}{44})}=0.975$

And the Margin of error is given by:

$Me= z_{\alpha/2} * SE=1.96*0.975=1.910$

c) The 95% confidence interval would be given by $2.009 \leq \mu_1 -\mu_2 \leq 5.83$ .

Step-by-step explanation:

Notation and previous concepts

$n_1 =35$ represent the sample of ships that carry fewer than 500 passengers

$n_2 =44$ represent the sample of ships that carry 500 or more passengers

$\bar x_1 =85.82$ represent the mean sample of of ships that carry fewer than 500 passengers

$\bar x_2 =81.90$ represent the mean sample of of ships that carry 500 or more passengers

$\sigma_1 =4.55$ represent the population deviation of ships that carry fewer than 500 passengers

$\sigma_2 =3.97$ represent the sample deviation of ships that carry 500 or more passengers

$\alpha=0.05$ represent the significance level

Confidence =95% or 0.95

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{(\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2})}$ (1)

Part a

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =85.82-81.90=3.92$

Part b: At 95% confidence, what is the margin of error?

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$

The standard error is given by the following formula:

$SE=\sqrt{(\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2})}$

And replacing we have:

$SE=\sqrt{(\frac{4.55^2}{35}+\frac{3.97^2}{44})}=0.975$

And the Margin of error is given by:

$Me= z_{\alpha/2} * SE=1.96*0.975=1.910$

Part c: What is a 95% confidence interval estimate of the difference between the population mean ratings for the two sizes of ships?

Confidence interval

Now we have everything in order to replace into formula (1):

$3.92-1.96\sqrt{(\frac{4.55^2}{35}+\frac{3.97^2}{44})}=2.009$

$3.92+1.96\sqrt{(\frac{4.55^2}{35}+\frac{3.97^2}{44})}=5.830$

So on this case the 95% confidence interval would be given by $2.009 \leq \mu_1 -\mu_2 \leq 5.83$ .

7 0

3 years ago

Solve x -9 = 8 HELP!!!!! I am dead over here help me!!!!

kumpel [21]

Answer:

x=17

Step-by-step explanation:

x-9=8

add nine on both sides

x-9+9=8+9

the nines on the side with the x cancel each other

x=17

3 0

3 years ago