Once the cake is removed from the oven, it has been exposed to the room temperature of 70°F. After 10 minutes, the cake's temperature decreased to 200°F, which is 150°F cooler than it initially was (350°F). As for the what is asked, 90°F is 260°F cooler than its original temperature (350°F).
This problem can be expressed in a ratio:
10mins:150<span>°F = N:260</span><span>°F
where N is how long it will take for</span><span> cake to cool to 90°F
</span>150<span>°FxN=10x260
</span>150N=2600
N=2600/150
N=17.33
N<span>≈20 minutes
Thus, it takes approximately 20 minutes </span><span>for the cake to cool to 90°F</span>
Answer:
m<F=50
Step-by-step explanation:
complementary angles mean that together they equal 90, we need to set up an equation to find x, and then put x into angle F to find its measurement :)
m<C+m<F=90
(2x+10)+(x+35)=90
calculate to find x!
x=15
now we put 15 into (x+35)
15+35=50
hope this helps!! :D
The volume at time <span>t = 25 seconds
since </span><span> V = 4 sqrt(t) cm3,
V(5)= 4*</span><span>sqrt(25)cm^3=4*5=20cm^3</span>
97, 19+(11+37)=19+(48)=67 and then add 30 because of 19 and 11 and you get 97
The answer to question 1 is B
the answer to question 2 is B
