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4 years ago

What is the value of the discriminant of the polynomial below? 3x^2+6x+5

1 answer:

4 0

$3x^2+6x+5 \\
a=3 \\ b=6 \\ c=5$

The discriminant of a quadratic polynomial:
$\Delta=b^2-4ac \\ \\
\Delta=6^2-4 \times 3 \times 5=36-60=\boxed{-24}$

The value of the discriminant is -24.

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Help me with this question please

bezimeni [28]

I am sorry if i am wrong but i am getting c or d

4 0

3 years ago

A plastic sack contains 20 green and yellow, 14 red and yellow, and 16 orange and yellow gummy treats. How much greater is the p

noname [10]

Answer:

Probability of choosing green and yellow treat is higher than Probability of choosing an orange and yellow treat by 0.08

Step-by-step explanation:

Given -

Green and yellow gummy treats = 20

Red and yellow gummy treats = 14

Orange and yellow gummy treats = 16

Total gummy treat = 20+14+16 = 50

Probability of choosing green and yellow treat = 20/50 = 0.4

Probability of choosing an orange and yellow treat = 16/50 = 0.32

Probability of choosing green and yellow treat is higher than Probability of choosing an orange and yellow treat by 0.08

4 0

3 years ago

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babymother [125]

The answer to number 16 is 0,15

8 0

3 years ago

Find the recursive quadratic formula of the sequence: 1, 3, 7, 13, 21

Anika [276]

The sequence

1, 3, 7, 13, 21, ...

has first-order differences

2, 4, 6, 8, ...

Let $a_n$ denote the original sequence, and $b_n$ the sequence of first-order differences. It's quite clear that

$b_n=2n$

for $n\ge1$ . By definition of first-order differences, we have

$b_n=a_{n+1}-a_n$

for $n\ge1$ , or

$a_{n+1}=a_n+2n$

By substitution, we have

$a_n=a_{n-1}+2(n-1)$

$\implies a_{n+1}=(a_{n-1}+2(n-1))+2n$

$\implies a_{n+1}=a_{n-1}+2(n+(n-1))$

$a_{n-1}=a_{n-2}+2(n-2)$

$\implies a_{n+1}=(a_{n-2}+2(n-2))+2(n+(n-1))$

$\implies a_{n+1}=a_{n-2}+2(n+(n-1)+(n-2))$

and so on, down to

$a_{n+1}=a_1+2(n+(n-1)+\cdots+2+1)$

You should know that

$1+2+\cdots+(n-1)+n=\dfrac{n(n+1)}2$

and we're given $a_1=1$ , so

$a_{n+1}=1+n(n+1)=n^2+n+1$

$a_n=(n-1)^2+(n-1)+1\implies\boxed{a_n=n^2-n+1}$

Alternatively, since we already know the sequence is supposed to be quadratic, we can look for coefficients $a,b,c$ such that

$a_n=an^2+bn+c$

We have

$a_1=a+b+c=1$

$a_2=4a+2b+c=3$

$a_3=9a+3b+c=7$

and we can solve this system for the 3 unknowns to find $a=1,b=-1,c=1$ .

4 0

4 years ago

(4x - 6)<br> (2x)<br> Find the value of x

Setler [38]

Answer:

1.5

Step-by-step explanation:

(4x - 6) (2x)

= 8x^2 - 12x

8x^2 = 12x

8x = 12

2x = 3

x = 1.5

6 0

3 years ago