Answer:
The area of triangle K is 16 times greater than the area of triangle J
Step-by-step explanation:
we know that
If Triangle K is a scaled version of Triangle J
then
Triangle K and Triangle J are similar
If two triangles are similar, then the ratio of its areas is equal to the scale factor squared
Let
z -----> the scale factor
Ak ------> the area of triangle K
Aj -----> the area of triangle J
so

we have

substitute



therefore
The area of triangle K is 16 times greater than the area of triangle J
7.9168 x 10^8
790000000 + 1680000 = 791680000
Answer:
214
Step-by-step explanation:
The set up would be x + (x + 1) + (x + 2) + (x + 3) = 854, naturally as the numbers are consecutive. Solving for x:
x + (x + 1) + (x + 2) + (x + 3) = 854,
x + x + 1 + x + 2 + x + 3 = 854,
4x + 1 + 2 + 3 = 854,
4x + 6 = 854,
4x = 854 - 6 = 848,
x = 848/4 = 212
The third number then should be 212 + 2 = 214
Rule of trigonometric functions:-
sin a = cos(90 - a)
Here a = 90°.
sin 90 = cos (90 - 90)
1 = cos 0.
cos 0 = 1.
So the cos 0 = 1.