Answer:
The force pulling down the ramp is 374.6 lb
The force pressing on a line perpendicular to the ramp is 927.1 lb
Step-by-step explanation:
Given;
weight of boat (mg) , w = 1000 lb
angle of inclination of the ramp, θ = 22 degrees.
The force pulling the boat down, which is 'mg' has two components; the parallel component of the force which is pulling down the ramp and the vertical component of the force which is force pressing on a line perpendicular to the ramp
Parallel component of the force, F = mgsinθ
F = wsinθ
F = 1000 sin(22)
F = 1000 x 0.3746
F = 374.6 lb
Vertical component of the force which is force pressing on a line perpendicular to the ramp.
F = mgCosθ
F = wCosθ
F = 1000 x Cos(22)
F = 1000 x 0.9271
F = 927.1 lb
