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❖ The equation is
n = 18
9 ÷ 1/2 = 9 x 2/1 = 18/1 = 18
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Answer:<em> </em><em>a/b + c/d = 14/45 ≈ 3.111</em>
Step-by-step explanation:
<em>a / b + c / d may have the smallest value, for example, if:</em>
<em>a = 1</em>
<em>b = 9</em>
<em>c = 2</em>
<em>d = 10</em>
<em>Therefore, we get:</em>
<em>1/9 + 2/10 = 14/45 ≈ 3.111</em>
Answer:
Probability (N more than 2) = 0.3773
Step-by-step explanation:
Given:
Average number of crashes (N) = 2.2
Find:
Probability (N more than 2)
Computation:
Probability (N more than 2) = [1-P(N=0)-P(N=1)-P(N=2)]
Probability (N more than 2) = [1 - e⁻²°² - 2.2e⁻²°² - (2.2²e⁻²°²)/2]
Probability (N more than 2) = 0.3773
Distributive
2(3+4+8+7)
(2x3)+(2x4)+(2x8)+(2x7
6+8+16+14
=44
Non-Distributive
2(3+4+8+7)
Add all the number in parenthesis
3+4=7+8=15+7=22
2(22)
=44
Combination of normal and binomial distributions.
Calculate probability of opening below 100m.
mean=175 m
standard deviation = 35 m
z=(100-175)/35=-15/7
p=P(Z<z)=0.01606229 from normal probability tables.
Calculate probability of at least one parachute opens below 100m
p=0.01606229n=5
x=0
P(X>0)
=1-P(x=0)
=1-C(5,0)p^x(1-p)^5
=1-1*0.01606229^0*(1-0.01606229)^5
=1-0.9222 (approximately)
=0.0778
Answer:
Probability that at least one of five cargoes will be damaged is 0.0778