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stich3 [128]
2 years ago
14

how do I delete my brainly account because when i do it, it says enter your password but I made my account with Go.ogle.

Mathematics
1 answer:
Brums [2.3K]2 years ago
6 0

Answer:

If the *account has a password, then use that password. Or try some other way of deleting it.  

Step-by-step explanation:

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What type of function would you use to model the height a bull thrown in the air travel over a period of time ?
tia_tia [17]
Airplane I DONT KNOW ANYTHING LOL
3 0
2 years ago
6. they were 300 people at a football match and 35% were adults, the rest were children a. what percentage were children​
ioda

Answer: 65%, 195 children

Step-by-step explanation: To get this, we just do 100-35 to get 65 percent. We can calculate this further, and do 300*0.65, and we get 195. Thus, there were 195 children.

4 0
2 years ago
Read 2 more answers
I need help please):
Neko [114]

Answer:

7) x = 5

8) x = 10

Step-by-step explanation:

7) 2x-3=x+2

x=5

8) 4x=2x+20

2x=20

x=10

7 0
3 years ago
What is the range of the function y=2x+1 for the domain 2<=x<=5?
egoroff_w [7]
So domain is the number you can use
range is the output your get from inputting the domain given
so from 2≤x≤5
since it is linear, we can be sure that we only need to test the endpoints of the domain to find the endpoints of the range

sub 2 for x
y=2(2)+1
y=4+1
y=5

sub 5 for x
y=2(5)+1
y=10+1
y=11

so range is from 5 to 11
in interval notation: [5,11]
in other notation 5≤y≤11
or
R={y|5≤y≤11}
5 0
3 years ago
Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they
Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276

Number of ways of choosing 3 students From all males

n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220

The probability that all are male of choosing '3' students

P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }

P(E) =  \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}

P(E) = 0.067 = 6.71%

<u><em>Final answer</em></u>:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

3 0
3 years ago
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