All categories

3 years ago

If I read 2/3 of a book that has 222 pages how many pages do I have left to read

Mathematics

2 answers:

ahrayia [7]3 years ago

6 0

It would be 74 pages i think

joja [24]3 years ago

3 0

Multiply 2/3 by 222 then subtract the number from 222 and you should get your answer

You might be interested in

Isaiah is preheating his oven before using it to bake. The initial temperature of the oven is 75° and the temperature will incre

antoniya [11.8K]

Answer:

12750 is the answer... god bless

4 0

3 years ago

Complete the identity.<br> 1) sec^4 x + sec^2 x tan^2 x - 2 tan^4 x = ?

Alecsey [184]

Answer:

See Explanation

Step-by-step explanation:

<em>Question like this are better answered if there are list of options; However, I'll simplify as far as the expression can be simplified</em>

Given

$sec^4 x + sec^2 x tan^2 x - 2 tan^4 x$

Required

Simplify

$(sec^2 x)^2 + sec^2 x tan^2 x - 2 (tan^2 x)^2$

Represent $sec^2x$ with a

Represent $tan^2x$ with b

The expression becomes

$a^2 + ab- 2 b^2$

Factorize

$a^2 + 2ab -ab- 2 b^2$

$a(a + 2b) -b(a+ 2 b)$

$(a -b) (a+ 2 b)$

Recall that

$a = sec^2x$

$b = tan^2x$

The expression $(a -b) (a+ 2 b)$ becomes

$(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

..............................................................................................................................

In trigonometry

$sec^2x =1 +tan^2x$

Subtract $tan^2x$ from both sides

$sec^2x - tan^2x =1 +tan^2x - tan^2x$

$sec^2x - tan^2x =1$

..............................................................................................................................

Substitute 1 for $sec^2x - tan^2x$ in $(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

$(1) (sec^2x+ 2 tan^2x)$

Open Bracket

$sec^2x+ 2 tan^2x$ ------------------This is an equivalence

$(secx)^2+ 2 (tanx)^2$

Solving further;

................................................................................................................................

In trigonometry

$secx = \frac{1}{cosx}$

$tanx = \frac{sinx}{cosx}$

Substitute the expressions for secx and tanx

................................................................................................................................

$(secx)^2+ 2 (tanx)^2$ becomes

$(\frac{1}{cosx})^2+ 2 (\frac{sinx}{cosx})^2$

Open bracket

$\frac{1}{cos^2x}+ 2 (\frac{sin^2x}{cos^2x})$

$\frac{1}{cos^2x}+ \frac{2sin^2x}{cos^2x}$

Add Fraction

$\frac{1 + 2sin^2x}{cos^2x}$ ------------------------ This is another equivalence

................................................................................................................................

In trigonometry

$sin^2x + cos^2x= 1$

Make $sin^2x$ the subject of formula

$sin^2x= 1 - cos^2x$

................................................................................................................................

Substitute the expressions for $1 - cos^2x$ for $sin^2x$

$\frac{1 + 2(1 - cos^2x)}{cos^2x}$

Open bracket

$\frac{1 + 2 - 2cos^2x}{cos^2x}$

$\frac{3 - 2cos^2x}{cos^2x}$ ---------------------- This is another equivalence

8 0

3 years ago

Please can someone help me out

lara31 [8.8K]

Answer:

380.1

Step-by-step explanation:

Area = 22/7 × 11 × 11 =380.3

8 0

3 years ago

What is the probability of picking a vowel from the word invite?

PIT_PIT [208]

6 total letters, 3 vowels. 3/6, or 1/2.

5 0

3 years ago

Read 2 more answers

Find the diagonal of a square whose sides are of the given measure. Given = 6sqrt2

jeyben [28]

Answer:

=12 units

Step-by-step explanation:

When a square is cut along one diagonal, it forms a right angled triangle whose legs are the sides of the square and the hypotenuse is the diagonal of the square.

Therefore, the Pythagoras theorem is used to find the hypotenuse.

a² + b² = c²

(6√2)²+(6√2)²=c²

72+72=c²

c²=144

c=√144

=12

The diagonals of the square measure 12 units each.

6 0

3 years ago