Help please I will give brainlyest 9th grade lidral arts

Mathematics

1 answer:

Assoli18 [71]2 years ago

6 0

-5 + 12 is 7

-2 - 8 is -10

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Parcc chapter 7 pythagorean theorem

Bumek [7]

So, we know that a^2 + b^2 = c^2. Right? That is called the Pythagorean Theorem.

In this case. We can say that 39 is a, 40 is b, and x is c.
NOTE: It doesn't really matter whether 39 is a or b. a & b are just the two legs of the right triangle.

So, if we say that 39 is a, 40 is b, and x is c. We can plug it into the Pythagorean Theorem.

39^2 + 40^2 = x^2

I'll let you take it from there.

7 0

3 years ago

The soccer team collector $800 at a carwash fundraiser they charge five dollars for small vehicles and $10 for large vehicles th

Nadusha1986 [10]

800 - 50 = 750
750 ÷ 5 =150
150 small vehicles were washed

7 0

3 years ago

Find the derivative of

kirill [66]

Answer:

$\displaystyle y'(1, \frac{3}{2}) = -3$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)
Functions
Function Notation
Terms/Coefficients
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

Step 1: Define

$\displaystyle y = \frac{3}{2x^2}$

$\displaystyle \text{Point} \ (1, \frac{3}{2})$

Step 2: Differentiate

[Function] Rewrite [Exponential Rule - Rewrite]: $\displaystyle y = \frac{3}{2}x^{-2}$
Basic Power Rule: $\displaystyle y' = -2 \cdot \frac{3}{2}x^{-2 - 1}$
Simplify: $\displaystyle y' = -3x^{-3}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{-3}{x^3}$

Step 3: Solve

Substitute in coordinate [Derivative]: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1^3}$
Evaluate exponents: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1}$
Divide: $\displaystyle y'(1, \frac{3}{2}) = -3$